C++ template name pretty print

问题

I have need to print indented template names for debugging purposes. For example, instead of single-line, I would like to indent name like this:

boost::phoenix::actor<
    boost::phoenix::composite<
      boost::phoenix::less_eval,
      boost::fusion::vector<
        boost::phoenix::argument<0>,
        boost::phoenix::argument<1>,

I started writing my own but is getting to be complicated. Is there an existing solution?

if there is not one, can you help me to finish up my implementation? I will post it if so.

Thanks

this is what typeid.name looks like,

boost::phoenix::actor<boost::phoenix::composite<boost::phoenix::less_eval, 
boost::fusion::vector<boost::phoenix::argument<0>, 
boost::phoenix::composite<boost::phoenix::multiplies_eval, 
boost::fusion::vector<boost::phoenix::argument<1>, boost::phoenix::argument<2>,
boost::fusion::void_, boost::fusion::void_, boost::fusion::void_, 
boost::fusion::void_, boost::fusion::void_, boost::fusion::void_, 
boost::fusion::void_, boost::fusion::void >, boost::fusion::void_, 
boost::fusion::void_, boost::fusion::void_, boost::fusion::void_, 
boost::fusion::void_, boost::fusion::void_, boost::fusion::void_, 
boost::fusion::void_> > >

this is my goal

 6 boost::phoenix::actor<
 7   boost::phoenix::composite<
 8     boost::phoenix::less_eval,
 9     boost::fusion::vector<
10       boost::phoenix::argument<0>,
11       boost::phoenix::composite<
12         boost::phoenix::multiplies_eval,
13         boost::fusion::vector<
14           boost::phoenix::argument<1>,
15           boost::phoenix::argument<2>,
16           boost::fusion::void_,
17           boost::fusion::void_,
18           boost::fusion::void_,
19           boost::fusion::void_,
20           boost::fusion::void_,
21           boost::fusion::void_,
22           boost::fusion::void_,
23           boost::fusion::void >, // indentation messed up
24           boost::fusion::void_,
25           boost::fusion::void_,
26           boost::fusion::void_,
27           boost::fusion::void_,
28           boost::fusion::void_,
29           boost::fusion::void_,
30           boost::fusion::void_,
31           boost::fusion::void_
32         >
33       >
34     >

so that I can actually read declaration

回答1:

Certainly not the most elegant piece, but this should get you going regarding the closing tags:

std::string indent(std::string str, const std::string &indent = "  ") {
    std::string indent_ = std::string("\n");
    size_t token = 0;

    while ((token = str.find_first_of("<>,", token)) != std::string::npos) {
        switch(str[token]) {
            case '<': indent_.append(indent);
            case ',': str.insert(token + 1, indent_);
                      break;
            case '>': indent_.erase(indent_.size() - indent.size());
                      str.insert(token, indent_);
        }

        token += indent_.size() + 1;            
        const size_t nw = str.find_first_not_of(" ", token);
        if(nw != std::string::npos) {
            str.erase(token, nw-token);
        }
    }

    return str;
}

回答2:

How about, copy to clipboard, then

$ xclip -o | clang-format

For example, this takes the OP's template to

boost::phoenix::actor <
boost::phoenix::composite<
    boost::phoenix::less_eval,
    boost::fusion::vector<
    boost::phoenix::argument<0>,
    boost::phoenix::composite<
        boost::phoenix::multiplies_eval,
        boost::fusion::vector<
        boost::phoenix::argument<1>, boost::phoenix::argument<2>,
        boost::fusion::void_, boost::fusion::void_,
        boost::fusion::void_, boost::fusion::void_,
        boost::fusion::void_, boost::fusion::void_,
        boost::fusion::void_, boost::fusion::void>,
        boost::fusion::void_, boost::fusion::void_,
        boost::fusion::void_, boost::fusion::void_,
        boost::fusion::void_, boost::fusion::void_,
        boost::fusion::void_, boost::fusion::void_> > >

Not ideal, because there's an error somewhere in it. But it makes it pretty easy to find the error (the extra > after the void in the middle should be moved to the end). If we fix it, we get

boost::phoenix::actor<boost::phoenix::composite<
    boost::phoenix::less_eval,
    boost::fusion::vector<
        boost::phoenix::argument<0>,
        boost::phoenix::composite<
            boost::phoenix::multiplies_eval,
            boost::fusion::vector<
                boost::phoenix::argument<1>, boost::phoenix::argument<2>,
                boost::fusion::void_, boost::fusion::void_,
                boost::fusion::void_, boost::fusion::void_,
                boost::fusion::void_, boost::fusion::void_,
                boost::fusion::void_, boost::fusion::void, boost::fusion::void_,
                boost::fusion::void_, boost::fusion::void_,
                boost::fusion::void_, boost::fusion::void_,
                boost::fusion::void_, boost::fusion::void_,
                boost::fusion::void_>>>>>

回答3:

minor adjustment of gf program, mainly not to split short templates

#ifndef PRETTY_NAME_HPP
#define PRETTY_NAME_HPP

#include <typeinfo>
#include <string>
#include <iostream>
#include <cxxabi.h>

#define TYPENAME(TYPE) typeid_name(typeid(TYPE).name())

std::string indent(std::string str, const std::string &indent = "  ") {
    std::string indent_ = std::string("\n");
    size_t token = 0;

    bool one_line = false;
    while ((token = str.find_first_of("<>,", token)) != std::string::npos) {
        size_t size = str.size();
        size_t close, open, comma;

        switch(str[token]) {
        case '<':
            close = str.find(">", token+1);
            open = str.find("<", token+1);
            comma = str.find(",", token+1);
            one_line = !(close > open) && !(comma < close);

            if (one_line) break;
            indent_.append(indent);

        case ',':
            str.insert(token + 1, indent_);
            break;

        case '>':
            if (!one_line) {
                indent_.erase(indent_.size() - indent.size());
                str.insert(token, indent_);
            }
            one_line = false;
        }

        token += 1 + str.size() - size;

        const size_t nw = str.find_first_not_of(" ", token);
        if(nw != std::string::npos) {
            str.erase(token, nw-token);
        }
    }

    return str;
}
std::string typeid_name(const char* name) {
// #ifdef HAVE_CXA_DEMANGLE
    size_t size;
    int status;
    char *buf = abi::__cxa_demangle(name, NULL, &size, &status);
    if (status  != 0) throw status;
    std::string string(buf);
    free(buf);
    return indent(string);
// #else
//     return name;
// #endif
}

#endif /* PRETTY_NAME_HPP */

来源：https://stackoverflow.com/questions/2885597/c-template-name-pretty-print

标签

c++

templates

typeinfo