i can't make num rows inside while looping

独自空忆成欢 提交于 2019-12-20 07:12:47

问题


i have tow tables first table : For products Second Table : For Categories

i want to show in browser like this

category1 (20) category2 (5) category3 (3)

$select_sub_cat = mysql_query("SELECT * FROM sub_cat WHERE ct_id='".$row_main['id']."' ");
while($row_sub = mysql_fetch_array($select_sub_cat))
{
  $select_num_sub = mysql_query("SELECT * FROM market WHERE sub_cat='".$row_sub['id']."' ");
  $row_num_sub = mysql_num_rows($select_num_sub);
  $smarty->assign('numb',$row_num_sub);

 $sub_cats[] = $row_sub;
}
$smarty->assign('sub_cats',$sub_cats);

回答1:


Try this:

$select_sub_cat = mysql_query("SELECT * FROM sub_cat WHERE ct_id='".$row_main['id']."' ");
while($row_sub = mysql_fetch_array($select_sub_cat))
{
  $select_num_sub = mysql_query("SELECT * FROM market WHERE sub_cat='".$row_sub['id']."' ");
  $smarty->assign('numb',$row_num_sub);

 $sub_cats[] = $row_sub;
 $sub_cats['count']=mysql_num_rows($select_num_sub);
}
$smarty->assign('sub_cats',$sub_cats);



回答2:


Try

$select_sub_cat = mysql_query("SELECT * FROM sub_cat WHERE ct_id='".$row_main['id']."' ");
while($row_sub = mysql_fetch_array($select_sub_cat))
{
  $select_num_sub = mysql_query("SELECT * FROM market WHERE sub_cat='".$row_sub['id']."' ");         
 $sub_cats[] = $row_sub;
 $sub_cats['count']=mysql_num_rows($select_num_sub);
}
$smarty->assign('sub_cats',$sub_cats);

and then call on your smarty :

{$sub_cats.name} ({$sub_cats.count}) // $sub_cats.name should be 'name' of category



来源:https://stackoverflow.com/questions/12927269/i-cant-make-num-rows-inside-while-looping

易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!