问题
If I have a User and Item model, and they have a many-to-many association with each other, how do I build a query that returns:
(1) All items that belong to any user named 'Bob'
I tried:
Item.query.filter(User.name == 'Bob')
Which returns all items regardless of the user's name (incorrect)
(2) All items that have the name 'shark' and belong to any user named 'Bob'
I tried:
Item.query.filter(User.name == 'Bob' & Item.name == 'shark')
Same as above, but only returns items named 'shark' regardless of the user's name. (incorrect)
My model definitions:
association_table = Table('items_users',
Column('itemid', Integer, ForeignKey('item.id'), primary_key=True),
Column('userid', Integer, ForeignKey('user.id'), primary_key=True)
)
class Item(Model):
# other fields...
# many to many association
users = relationship('User', secondary=association_table, lazy='dynamic', backref=backref('items', lazy='dynamic'))
class User(Model):
# other fields...
What would be appropriate syntax for two queries?
回答1:
You need to join the tables you will query, so that filtering one will filter the combined row associated with the other. Since you have defined a relationship between the two models, you can join on it rather than specifying a join condition manually.
Item.query.join(Item.users).filter(User.name == 'bob')
Item.query.join(Item.users).filter(User.name == 'bob', Item.name == 'shark')
Working with relationships and joins is covered in the comprehensive tutorial in the SQLAlchemy docs.
来源:https://stackoverflow.com/questions/32575502/how-to-query-many-to-many-based-on-some-constraints-in-flask-sqlalchemy