问题
I have to different vectors
mpl::vector<Type1, Type2...>
mpl::vector<Type3, Type4...>
I'd like to "concatenate" them to form:
mpl::vector<Type1, Type2, Type3, Type4...>
This would allow me to prepare vector templates and reuse them afterwards. There are different solutions to my problem, but this approach seems most appropriate to me.
Thanks...
回答1:
The libaray native supported function boost::mpl::joint_view is probably a better choice. It is optimized and lazy-evaluated.
http://www.boost.org/doc/libs/1_55_0/libs/mpl/doc/refmanual/joint-view.html
回答2:
Like this:
// include the appropriate headers
typedef mpl::vector<Type1, Type2> first_type;
typedef mpl::vector<Type3, Type4> second_type;
typedef mpl::copy<first_type::type, mpl::back_inserter<second_type> >::type concat_type;
回答3:
You can use mpl::copy, which uses mpl::fold internally.
typedef mpl::vector<T0, T1> s0;
typedef mpl::vector<T2, T3> s1;
typedef mpl::copy<
s1,
mpl::back_inserter<s0>
>::type concatenated;
BOOST_MPL_ASSERT((
mpl::equal<
concatenated,
mpl::vector<T0, T1, T2, T3>
>
));
来源:https://stackoverflow.com/questions/19575018/how-to-concatenate-boostmplvectors