问题
Using gcc, when I ask for an object/variable's type using typeid, I get a different result from the type_info::name method from what I'd expect to get on Windows. I Googled around a bit, and found out that RTTI names are implementation-specific.
Problem is, I want to get a type's name as it would be returned on Windows. Is there an easy way to do this?
回答1:
If it's what you're asking, there is no compiler switch that would make gcc behave like msvc regarding the name returned by type_info::name().
However, in your code you can rely on the gcc specific __cxa_demangle function.
There is in fact an answer on SO that addresses your problem.
Reference: libstdc++ manual, Chapter 40. Demangling.
回答2:
c++ function names really include all the return and argument type information as well as the class and method name. When compiled, they are 'mangled' into a standard form (standard for each compiler) that can act as an assembler symbol and includes all the type information.
You need to run a function or program to reverse this mangling, called a demangler.
try running
c++filt myoutput.txt
on the output of the function. This demangles the real symbol name back into a human readable form.
回答3:
Based on this other question Is there an online name demangler for C++? I've written a online tool for this: c++filtjs
来源：https://stackoverflow.com/questions/2085239/can-i-ungarble-gccs-rtti-names