问题
What command, or collection of commands, can I use to return all file extensions in a directory (including sub-directories)?
Right now, I'm using different combinations of ls and grep, but I can't find any scalable solution.
回答1:
How about this:
find . -type f -name '*.*' | sed 's|.*\.||' | sort -u
回答2:
find . -type f | sed 's|.*\.||' | sort -u
Also works on mac.
回答3:
list all extensions and their counts of current and all sub-directories
ls -1R | sed 's/[^\.]*//' | sed 's/.*\.//' | sort | uniq -c
回答4:
if you are using Bash 4+
shopt -s globstar
for file in **/*.*
do
echo "${file##*.}
done
Ruby(1.9+)
ruby -e 'Dir["**/*.*"].each{|x|puts x.split(".")[-1]}' | sort -u
回答5:
Yet another solution using find (that should even sort file extensions with embedded newlines correctly):
# [^.]: exclude dotfiles
find . -type f -name "[^.]*.*" -exec bash -c '
printf "%s\000" "${@##*.}"
' argv0 '{}' + |
sort -uz |
tr '\0' '\n'
回答6:
Boooom another:
find * | awk -F . {'print $2'} | sort -u
回答7:
ls -1 | sed 's/.*\.//' | sort -u
Update: You are correct Matthew. Based on your comment, here is an updated version:
ls -R1 | egrep -C 0 "[^\.]+\.[^\./:]+$" | sed 's/.*\.//' | sort -u
回答8:
I was just quickly trying this as I was searching Google for a good answer. I am more Regex inclined than Bash, but this also works for subdirectories. I don't think includes files without extensions either:
ls -R | egrep '(\.\w+)$' -o | sort | uniq -c | sort -r
来源:https://stackoverflow.com/questions/4998290/how-to-find-all-file-extensions-recursively-from-a-directory