Proper Way to Retrieve More than 128 Documents with RavenDB

问题

I know variants of this question have been asked before (even by me), but I still don't understand a thing or two about this...

It was my understanding that one could retrieve more documents than the 128 default setting by doing this:

session.Advanced.MaxNumberOfRequestsPerSession = int.MaxValue;

And I've learned that a WHERE clause should be an ExpressionTree instead of a Func, so that it's treated as Queryable instead of Enumerable. So I thought this should work:

public static List<T> GetObjectList<T>(Expression<Func<T, bool>> whereClause)
{
    using (IDocumentSession session = GetRavenSession())
    {
        return session.Query<T>().Where(whereClause).ToList();                
    }
}

However, that only returns 128 documents. Why?

Note, here is the code that calls the above method:

RavenDataAccessComponent.GetObjectList<Ccm>(x => x.TimeStamp > lastReadTime);

If I add Take(n), then I can get as many documents as I like. For example, this returns 200 documents:

return session.Query<T>().Where(whereClause).Take(200).ToList();

Based on all of this, it would seem that the appropriate way to retrieve thousands of documents is to set MaxNumberOfRequestsPerSession and use Take() in the query. Is that right? If not, how should it be done?

For my app, I need to retrieve thousands of documents (that have very little data in them). We keep these documents in memory and used as the data source for charts.

** EDIT **

I tried using int.MaxValue in my Take():

return session.Query<T>().Where(whereClause).Take(int.MaxValue).ToList();

And that returns 1024. Argh. How do I get more than 1024?

** EDIT 2 - Sample document showing data **

{
  "Header_ID": 3525880,
  "Sub_ID": "120403261139",
  "TimeStamp": "2012-04-05T15:14:13.9870000",
  "Equipment_ID": "PBG11A-CCM",
  "AverageAbsorber1": "284.451",
  "AverageAbsorber2": "108.442",
  "AverageAbsorber3": "886.523",
  "AverageAbsorber4": "176.773"
}

回答1:

The Take(n) function will only give you up to 1024 by default. However, you can change this default in Raven.Server.exe.config:

<add key="Raven/MaxPageSize" value="5000"/>

For more info, see: http://ravendb.net/docs/intro/safe-by-default

回答2:

It is worth noting that since version 2.5, RavenDB has an "unbounded results API" to allow streaming. The example from the docs shows how to use this:

var query = session.Query<User>("Users/ByActive").Where(x => x.Active);
using (var enumerator = session.Advanced.Stream(query))
{
    while (enumerator.MoveNext())
    {
        User activeUser = enumerator.Current.Document;
    }
}

There is support for standard RavenDB queries, Lucence queries and there is also async support.

The documentation can be found here. Ayende's introductory blog article can be found here.

回答3:

The Take(n) function will only give you up to 1024 by default. However, you can use it in pair with Skip(n) to get all

        var points = new List<T>();
        var nextGroupOfPoints = new List<T>();
        const int ElementTakeCount = 1024;
        int i = 0;
        int skipResults = 0;

        do
        {
            nextGroupOfPoints = session.Query<T>().Statistics(out stats).Where(whereClause).Skip(i * ElementTakeCount + skipResults).Take(ElementTakeCount).ToList();
            i++;
            skipResults += stats.SkippedResults;

            points = points.Concat(nextGroupOfPoints).ToList();
        }
        while (nextGroupOfPoints.Count == ElementTakeCount);

        return points;

RavenDB Paging

回答4:

Number of request per session is a separate concept then number of documents retrieved per call. Sessions are short lived and are expected to have few calls issued over them.

If you are getting more then 10 of anything from the store (even less then default 128) for human consumption then something is wrong or your problem is requiring different thinking then truck load of documents coming from the data store.

RavenDB indexing is quite sophisticated. Good article about indexing here and facets here.

If you have need to perform data aggregation, create map/reduce index which results in aggregated data e.g.:

Index:

    from post in docs.Posts
    select new { post.Author, Count = 1 }

    from result in results
    group result by result.Author into g
    select new
    {
       Author = g.Key,
       Count = g.Sum(x=>x.Count)
    }

Query:

session.Query<AuthorPostStats>("Posts/ByUser/Count")(x=>x.Author)();

回答5:

You can also use a predefined index with the Stream method. You may use a Where clause on indexed fields.

var query = session.Query<User, MyUserIndex>();
var query = session.Query<User, MyUserIndex>().Where(x => !x.IsDeleted);

using (var enumerator = session.Advanced.Stream<User>(query))
{
    while (enumerator.MoveNext())
    {
        var user = enumerator.Current.Document;
        // do something
    }
}

Example index:

public class MyUserIndex: AbstractIndexCreationTask<User>
{
    public MyUserIndex()
    {
        this.Map = users =>
            from u in users
            select new
            {
                u.IsDeleted,
                u.Username,
            };
    }
}

Documentation: What are indexes? Session : Querying : How to stream query results?

Important note: the Stream method will NOT track objects. If you change objects obtained from this method, SaveChanges() will not be aware of any change.

Other note: you may get the following exception if you do not specify the index to use.

InvalidOperationException: StreamQuery does not support querying dynamic indexes. It is designed to be used with large data-sets and is unlikely to return all data-set after 15 sec of indexing, like Query() does.

来源：https://stackoverflow.com/questions/10048943/proper-way-to-retrieve-more-than-128-documents-with-ravendb

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