How to use Bash to create a folder if it doesn't already exist?

问题

#!/bin/bash
if [!-d /home/mlzboy/b2c2/shared/db]; then
    mkdir -p /home/mlzboy/b2c2/shared/db;
fi;

This doesn't seem to work. Can anyone help?

回答1:

First, in bash "[" is just a command, which expects string "]" as a last argument, so the whitespace before the closing bracket (as well as between "!" and "-d" which need to be two separate arguments too) is important:

if [ ! -d /home/mlzboy/b2c2/shared/db ]; then
  mkdir -p /home/mlzboy/b2c2/shared/db;
fi

Second, since you are using -p switch to mkdir, this check is useless, because this is what does in the first place. Just write:

mkdir -p /home/mlzboy/b2c2/shared/db;

and thats it.

回答2:

There is actually no need to check whether it exists or not. Since you already wants to create it if it exists , just mkdir will do

mkdir -p /home/mlzboy/b2c2/shared/db

回答3:

Simply do:

mkdir /path/to/your/potentially/existing/folder

mkdir will throw an error if the folder already exists. To ignore the errors write:

mkdir -p /path/to/your/potentially/existing/folder

No need to do any checking or anything like that.

---

For reference:

-p, --parents no error if existing, make parent directories as needed http://man7.org/linux/man-pages/man1/mkdir.1.html

回答4:

You need spaces inside the [ and ] brackets:

#!/bin/bash
if [ ! -d /home/mlzboy/b2c2/shared/db ] 
then
    mkdir -p /home/mlzboy/b2c2/shared/db
fi

回答5:

Cleaner way, exploit shortcut evaluation of shell logical operators. Right side of the operator is executed only if left side is true.

[ ! -d /home/mlzboy/b2c2/shared/db ] && mkdir -p /home/mlzboy/b2c2/shared/db

回答6:

I think you should re-format your code a bit:

#!/bin/bash
if [ ! -d /home/mlzboy/b2c2/shared/db ]; then
    mkdir -p /home/mlzboy/b2c2/shared/db;
fi;

来源：https://stackoverflow.com/questions/4906579/how-to-use-bash-to-create-a-folder-if-it-doesnt-already-exist