问题
For debugging purposes, I'd like to see the raw request that is going to be sent. Is there a way to get this without a HTTP monitor directly from the API of HttpPost or HttpClient?
I found some "almost" duplicate questions, but not for this particular one
回答1:
You can set some environment variables for Apache HttpClient (example tested for 4.3.2).
System.setProperty("org.apache.commons.logging.Log","org.apache.commons.logging.impl.SimpleLog");
System.setProperty("org.apache.commons.logging.simplelog.showdatetime", "true");
System.setProperty("org.apache.commons.logging.simplelog.log.org.apache.http.wire", "DEBUG");
There are also some more variables for debugging:
System.setProperty("org.apache.commons.logging.simplelog.log.org.apache.http.impl.conn", "DEBUG");
System.setProperty("org.apache.commons.logging.simplelog.log.org.apache.http.impl.client", "DEBUG");
System.setProperty("org.apache.commons.logging.simplelog.log.org.apache.http.client", "DEBUG");
System.setProperty("org.apache.commons.logging.simplelog.log.org.apache.http", "DEBUG");
回答2:
Try this:
HttpClient client = new HttpClient();
PostMethod method = new PostMethod(url);
method.setParameter(...., ....);
to retrieve the URI
System.out.println("getUri: " + method.getURI());
to retrieve the parameters in POST
method.getRequestEntity().writeRequest(System.out);
回答3:
org.apache.http.client.fluent.Request#viaProxy
This method can make your request pass through proxy server, so your can launch a local proxy server, for example Fiddler, so this debugging proxy can show the details of http request and response.
回答4:
Try enabling DEBUG
mode in your logging configurations, if you're using log4j
you can add this to the log4j.xml
file of your project
<root>
<priority value="DEBUG" />
<appender-ref ref="FILE" />
</root>
You will have the full request headers, params, body, etc, logged in your logs files.
来源:https://stackoverflow.com/questions/10826001/using-apache-httpclient-how-can-one-see-the-raw-request-string-before-its-bei