问题
In my web app I'm using Newtonsoft.Json and I have following object
[Newtonsoft.Json.JsonObject(Title = "MyCar")]
public class Car
{
[Newtonsoft.Json.JsonProperty(PropertyName = "name")]
public string Name{get;set;}
[Newtonsoft.Json.JsonProperty(PropertyName = "owner")]
public string Owner{get;set;}
}
and I want serialize them with root name (class name). This is desired format using
{'MyCar':
{
'name': 'Ford',
'owner': 'John Smith'
}
}
I know that I can do that with anonymous object, but is any property or another way in Newtonsoft.Json library?
回答1:
Use anonymous class
Shape your model the way you want using anonymous classes:
var root = new
{
car = new
{
name = "Ford",
owner = "Henry"
}
};
string json = JsonConvert.SerializeObject(root);
回答2:
I found an easy way to render this out... simply declare a dynamic object and assign the first item within the dynamic object to be your collection class...This example assumes you're using Newtonsoft.Json
private class YourModelClass
{
public string firstName { get; set; }
public string lastName { get; set; }
}
var collection = new List<YourModelClass>();
var collectionWrapper = new {
myRoot = collection
};
var output = JsonConvert.SerializeObject(collectionWrapper);
What you should end up with is something like this:
{"myRoot":[{"firstName":"John", "lastName": "Citizen"}, {...}]}
回答3:
You can easily create your own serializer
var car = new Car() { Name = "Ford", Owner = "John Smith" };
string json = Serialize(car);
string Serialize<T>(T o)
{
var attr = o.GetType().GetCustomAttribute(typeof(JsonObjectAttribute)) as JsonObjectAttribute;
var jv = JValue.FromObject(o);
return new JObject(new JProperty(attr.Title, jv)).ToString();
}
回答4:
string Json = JsonConvert.SerializeObject(new Car { Name = "Ford", Owner = "John Smith" }, Formatting.None);
for the root element use GlobalConfiguration.
回答5:
A very simple approach for me is just to create 2 classes.
public class ClassB
{
public string id{ get; set; }
public string name{ get; set; }
public int status { get; set; }
public DateTime? updated_at { get; set; }
}
public class ClassAList
{
public IList<ClassB> root_name{ get; set; }
}
And when you going to do serialization:
var classAList = new ClassAList();
//...
//assign some value
//...
var jsonString = JsonConvert.SerializeObject(classAList)
Lastly, you will see your desired result as the following:
{
"root_name": [
{
"id": "1001",
"name": "1000001",
"status": 1010,
"updated_at": "2016-09-28 16:10:48"
},
{
"id": "1002",
"name": "1000002",
"status": 1050,
"updated_at": "2016-09-28 16:55:55"
}
]
}
Hope this helps!
回答6:
Well, you can at least tell Json.NET to include the type name: http://www.newtonsoft.com/json/help/html/T_Newtonsoft_Json_TypeNameHandling.htm . Newtonsoft.Json.JsonSerializer jser = new Newtonsoft.Json.JsonSerializer();
jser.TypeNameHandling = TypeNameHandling.Objects;
The type will be included at the beginning in the "$type" property of the object.
This is not exactly what you are looking for, but it was good enough for me when facing a similiar problem.
回答7:
Sorry, my english is not that good. But i like to improve the upvoted answers. I think that using Dictionary is more simple and clean.
class Program
{
static void Main(string[] args)
{
agencia ag1 = new agencia()
{
name = "Iquique",
data = new object[] { new object[] {"Lucas", 20 }, new object[] {"Fernando", 15 } }
};
agencia ag2 = new agencia()
{
name = "Valparaiso",
data = new object[] { new object[] { "Rems", 20 }, new object[] { "Perex", 15 } }
};
agencia agn = new agencia()
{
name = "Santiago",
data = new object[] { new object[] { "Jhon", 20 }, new object[] { "Karma", 15 } }
};
Dictionary<string, agencia> dic = new Dictionary<string, agencia>
{
{ "Iquique", ag1 },
{ "Valparaiso", ag2 },
{ "Santiago", agn }
};
string da = Newtonsoft.Json.JsonConvert.SerializeObject(dic);
Console.WriteLine(da);
Console.ReadLine();
}
}
public class agencia
{
public string name { get; set; }
public object[] data { get; set; }
}
This code generate the following json (This is desired format)
{
"Iquique":{
"name":"Iquique",
"data":[
[
"Lucas",
20
],
[
"Fernando",
15
]
]
},
"Valparaiso":{
"name":"Valparaiso",
"data":[
[
"Rems",
20
],
[
"Perex",
15
]
]
},
"Santiago":{
"name":"Santiago",
"data":[
[
"Jhon",
20
],
[
"Karma",
15
]
]
}
}
回答8:
I hope this help.
//Sample of Data Contract:
[DataContract(Name="customer")]
internal class Customer {
[DataMember(Name="email")] internal string Email { get; set; }
[DataMember(Name="name")] internal string Name { get; set; }
}
//This is an extension method useful for your case:
public static string JsonSerialize<T>(this T o)
{
MemoryStream jsonStream = new MemoryStream();
var serializer = new System.Runtime.Serialization.Json.DataContractJsonSerializer(typeof(T));
serializer.WriteObject(jsonStream, o);
var jsonString = System.Text.Encoding.ASCII.GetString(jsonStream.ToArray());
var props = o.GetType().GetCustomAttributes(false);
var rootName = string.Empty;
foreach (var prop in props)
{
if (!(prop is DataContractAttribute)) continue;
rootName = ((DataContractAttribute)prop).Name;
break;
}
jsonStream.Close();
jsonStream.Dispose();
if (!string.IsNullOrEmpty(rootName)) jsonString = string.Format("{{ \"{0}\": {1} }}", rootName, jsonString);
return jsonString;
}
//Sample of usage
var customer = new customer {
Name="John",
Email="john@domain.com"
};
var serializedObject = customer.JsonSerialize();
回答9:
[Newtonsoft.Json.JsonObject(Title = "root")]
public class TestMain
this is the only attrib you need to add to get your code working.
来源：https://stackoverflow.com/questions/16294963/json-net-serialize-object-with-root-name