问题
Java is new to me.
I am executing a batch file using Runtime.getRuntime.exec(filename.bat) and this batch file executes a commandant encrypt.password -Dvalue=somevalue>log.txt and redirects its output to a log.txt file.
Problem that I am facing is batch file is working fine if I run it manually however when program executes it ,it just creates blank 'log.txt'
Content of mybat.bat batch file is as below:
cd/
c:
cd c:/ant_builds/thinclient
ant encrypt.password -Dvalue=someValue >C:/log.txt
Java code is as below:
Process p=Runtime.getRuntime.exec("C:\mybat.bat");
p.waitFor();
It seems that after creating the log file,meantime command is executing control comes out from process.
I have read almost 50 threads here however did not get the solution. Please help me out.
回答1:
Use ProcessBuilder to create your process and call redirectOutput(File) to redirect and append output to a file.
Try this code:
public class Test {
ProcessBuilder builder;
Path log;
public Test() {
try
{
log = Paths.get("C:\\log.txt");
if (!Files.exists(log))
{
Files.createFile(log);
}
builder = new ProcessBuilder("ant", "encrypt.password", "-Dvalue=someValue");
builder.directory(Paths.get("C:\\ant_builds\\thinclient").toFile());
builder.redirectOutput(ProcessBuilder.Redirect.appendTo(log.toFile()));
builder.start();
}
catch (IOException e)
{
e.printStackTrace();
}
}
public static void main(String[] args) {
new Test();
}
}
For jdk 1.6 or less, use the following code:
public class Test {
ProcessBuilder builder;
Path log;
Process process;
BufferedReader br;
PrintWriter pw;
Charset charset = Charset.forName("UTF-8");
public Test() {
try {
log = new File("C:\\log.txt");
if (!log.exists()) {
log.createNewFile();
}
builder = new ProcessBuilder("ant", "encrypt.password","-Dvalue=someValue");
builder.directory(new File("C:\\ant_builds\\thinclient"));
builder.redirectErrorStream(true);
process = builder.start();
br = new BufferedReader(new InputStreamReader(process.getInputStream(),charset));
pw = new PrintWriter(new OutputStreamWriter(new FileOutputStream(log, true), charset));
(new Thread() {
public void run() {
try {
while (process.isAlive()) {
String s = null;
while ((s = br.readLine()) != null) {
pw.print(s);
pw.flush();
}
}
br.close();
pw.close();
} catch (IOException e) {
e.printStackTrace();
}
}
}).start();
} catch (IOException e) {
e.printStackTrace();
}
}
public static void main(String[] args) {
new Test();
}
}
I'm not sure about the order and list of ProcessBuilder arguments so try to play with them to get your code working.
回答2:
You can also read commands from a common file and redirect output and erros to a sepearate files. Redirect.appendTo is to avoid the process from overiting the existing logs.
Try this code:
try {
File commands = new File("D:/Sample/Commands.txt");
File output = new File("D:/Sample/Output.txt");
File errors = new File("D:/Sample/ErrorsLog.txt");
ProcessBuilder pb = new ProcessBuilder("cmd");
System.out.println(pb.redirectInput());
System.out.println(pb.redirectOutput());
System.out.println(pb.redirectError());
pb.redirectInput(commands);
pb.redirectError(Redirect.appendTo(errors));
pb.redirectOutput(Redirect.appendTo(output));
pb.redirectInput();
pb.redirectOutput();
pb.redirectError();
pb.start();
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
来源:https://stackoverflow.com/questions/27547874/java-redirecting-output-of-bat-file-in-other-text-file-using-exec-method