问题
I want to convert a String myString like that:
[ ["cd",5,6,7], ["rtt",55,33,12], ["by65",87,87,12] ]
into an ArrayList<CustomClass>
Where CustomClass have constructor :
public CustomClass (String name, int num1, int num2, int num3)
I tried first to create ArrayList of Strings :
List<String> List = new ArrayList<String>(Arrays.asList(myString.split("[")));
Didn't worked for me...
How can I get something like that:
List - {CustomClass,CustomClass,CustomClass,CustomClass}
first CustomClass = CustomClass.name="cd" , CustomClass.num1=5,CustomClass.num2=7...
second CustomClass = CustomClass.name="rtt",CustomClass.num1=55,CustomClass.num2=55...
and so on...
回答1:
You can do something like. If you cant guarantee the string formats then you may have to add additional checks for spliced array length and indexing.
import java.util.ArrayList;
import java.util.List;
import java.util.regex.Matcher;
import java.util.regex.Pattern;
class CustomClass {
String name;
int num1;
int num2;
int num3;
public CustomClass(String name, int num1, int num2, int num3) {
super();
this.name = name;
this.num1 = num1;
this.num2 = num2;
this.num3 = num3;
}
}
public class Sample {
public static void main(String[] args) {
String str = "[ [\"cd\",5,6,7], [\"rtt\",55,33,12], [\"by65\",87,87,12] ]";
Pattern p = Pattern.compile("\\[(.*?)\\]");
Matcher m = p.matcher(str.substring(1));
List<CustomClass> customList = new ArrayList<CustomClass>();
while (m.find()) {
String[] arguments = m.group(1).split(",");
customList.add(new CustomClass(arguments[0],
Integer.parseInt(arguments[1]),
Integer.parseInt(arguments[2]),
Integer.parseInt(arguments[3])));
}
}
}
Gson solution
public static void main(String[] args) {
String json = "[ [\"cd\",5,6,7], [\"rtt\",55,33,12], [\"by65\",87,87,12] ]";
List<CustomClass> customList = new ArrayList<CustomClass>();
String[][] data = new Gson().fromJson(json, String[][].class);
for (String[] strArray : data){
customList.add(new CustomClass(strArray[0],
Integer.parseInt(strArray[1]),
Integer.parseInt(strArray[2]),
Integer.parseInt(strArray[3])));
}
System.out.println(customList);
}
回答2:
Here's a quick "by-hand" parser for you.
public static List<CustomClass> parseString(String str) {
String [] elements = str.split("\\[");
List <CustomClass> result = new ArrayList<CustomClass>();
for (String elem : elements) {
if (elem.contains("]")) {
String seq = elem.substring(0, elem.indexOf(']'));
String [] tokens = seq.split(",");
result.add(new CustomClass(tokens[0].substring(1,tokens[0].length()-1),
Integer.parseInt(tokens[1]),
Integer.parseInt(tokens[2]),
Integer.parseInt(tokens[3])));
}
}
return result;
}
Beware that I relied on guaranteed correct input. You might want to tweak this one for what you need.
来源:https://stackoverflow.com/questions/24998055/convert-string-into-arraylistmyclass