问题
I have an activity table in my application. It has a project ID, an activity ID, a baseline finish date, an actual finish date a planned finish date and a late finish date.
I want to take the count of activity ID for each week of the project in each date column. I then want to take each of these date columns and plot them against each other.
The end result would be a curve that shows the number of activities in week 2 compared to the actual number of activities in week 2 compared to the number of planned activities in week two and the number of late-finish activities in week 2.
I can do this to get the data to show up...
SELECT ACTIVITY.PROJECTOBJECTID,
ACTIVITY.OBJECTID,
TRUNC(ACTIVITY.BASELINEFINISHDATE,'W')+7 AS BLFIN,
TRUNC(ACTIVITY.ACTUALFINISHDATE,'W')+7 AS AFIN,
TRUNC(ACTIVITY.FINISHDATE,'W')+7 AS FIN,
TRUNC(ACTIVITY.REMAININGLATEFINISHDATE,'W')+7 AS LFIN
FROM PXRPTUSER.ACTIVITY ACTIVITY
WHERE (ACTIVITY.PROJECTOBJECTID = :POID)
But, now I have four date columns. Ideally I want four count columns with a single date column. Here is a sample of the data I have to work with.
PID AID BLFIN AFIN FIN LFIN
39987 5874494 2/22/2015 2/22/2015 6/15/2015
39987 5874495 2/22/2015 2/22/2015 6/15/2015
39987 5874496 2/22/2015 2/22/2015 6/15/2015
39987 5874497 2/22/2015 2/22/2015 6/15/2015
39987 5874498 2/22/2015 2/22/2015 6/15/2015
39987 5874499 4/22/2015 4/22/2015 6/15/2015
39987 5874500 2/22/2015 2/22/2015 6/15/2015
39987 5874501 2/22/2015 2/22/2015 6/15/2015
39987 5874502 4/8/2015 4/8/2015 6/15/2015
39987 5874503 4/8/2015 4/8/2015 6/15/2015
39987 5874504 4/8/2015 4/8/2015 6/15/2015
39987 5874505 5/15/2015 5/15/2015 6/15/2015
39987 5874506 5/15/2015 5/15/2015 6/15/2015
39987 5874507 4/8/2015 4/8/2015 6/15/2015
39987 5874508 4/8/2015 4/8/2015 6/15/2015
39987 5874509 4/8/2015 4/8/2015 6/15/2015
39987 5874510 4/8/2015 4/8/2015 6/15/2015
39987 5874511 4/8/2015 4/8/2015 6/15/2015
39987 5874512 4/8/2015 4/8/2015 6/15/2015
39987 5874513 4/8/2015 4/8/2015 6/15/2015
39987 5874514 4/8/2015 4/8/2015 6/15/2015
39987 5874515 4/8/2015 4/8/2015 6/15/2015
39987 5874516 4/8/2015 4/8/2015 6/15/2015
39987 5874517 4/8/2015 4/8/2015 6/15/2015
39987 5874537 2/22/2015 2/22/2015 6/15/2015
39987 5874538 2/22/2015 2/22/2015 6/15/2015
39987 5874539 2/22/2015 2/22/2015 6/15/2015
39987 5874540 2/22/2015 2/22/2015 2/22/2015
39987 5874542 2/22/2015 2/22/2015 6/15/2015
39987 5874543 2/22/2015 2/22/2015 6/15/2015
39987 5874544 2/22/2015 2/22/2015 6/15/2015
39987 5874545 2/22/2015 2/22/2015 6/15/2015
39987 5874546 2/22/2015 2/22/2015 6/15/2015
39987 5874547 2/22/2015 2/22/2015 6/15/2015
39987 5874548 2/22/2015 2/22/2015 6/15/2015
39987 5874549 2/22/2015 2/22/2015 6/15/2015
39987 5874550 2/22/2015 2/22/2015 6/15/2015
39987 5874551 2/22/2015 2/22/2015 6/15/2015
39987 5874552 2/22/2015 2/22/2015 6/15/2015
39987 5874553 2/22/2015 2/22/2015 6/15/2015
39987 5874554 2/22/2015 2/22/2015 6/15/2015
回答1:
Query below gives described results. Column WKN is week number in ISO standard, you may want to change it to something else, eg. 'WW'. Also if you have dates from different years you have to concatenate year in query (attach year to wkn in bf, af, pf and lf subqueries).
with
bf as (select to_char(blfin, 'iw') wkn, count(aid) cnt
from activity group by to_char(blfin, 'iw')),
af as (select to_char(afin, 'iw') wkn, count(aid) cnt
from activity group by to_char(afin, 'iw')),
pf as (select to_char(fin, 'iw') wkn, count(aid) cnt
from activity group by to_char(fin, 'iw')),
lf as (select to_char(lfin, 'iw') wkn, count(aid) cnt
from activity group by to_char(lfin, 'iw'))
select wkn, nvl(bf.cnt, 0) as baseline, nvl(af.cnt, 0) as actual,
nvl(pf.cnt, 0) as planned, nvl(lf.cnt, 0) as late
from bf
full join af using (wkn)
full join pf using (wkn)
full join lf using (wkn)
where wkn is not null
order by wkn
Results:
WKN BASELINE ACTUAL PLANNED LATE
--- -------- -------- -------- --------
08 24 0 24 1
15 14 0 14 0
17 1 0 1 0
20 2 0 2 0
25 0 0 0 40
来源：https://stackoverflow.com/questions/28652040/oracle-sql-multiple-columns-aligned-to-a-single-range-legend