Probably simple but confusing assignment error

问题

#include <stdio.h>

int main() {
    char gradesList[5];
    gradesList[2] = "X";
    printf("%c", gradesList[2]);
}

When I try to run this code I get these errors:

Incompatible pointer to integer conversion

Assignment makes integer from pointer without a cast

回答1:

You have to assign a char not a pointer to a string literal. Use ' instead of "

gradesList[2] = 'X';

---

In C string literals are represented using double qoutes, i.e. ". And char are represented using single quotes, i.e. '.

Since you have declared gradesList as a char array. And are trying to assign a pointer to a string literal, you are getting this error.

回答2:

Anything inside double quote is considered as string.

you should use :

gradesList[2] = 'X';

来源：https://stackoverflow.com/questions/33603276/probably-simple-but-confusing-assignment-error