Joining Flattened Data

北城以北 提交于 2019-11-27 04:52:02

Not exactly sure how your dataset looks like, so I'm just going to write a basic example. Assuming a structure something like this:

- projects
  - key
    - name: string
    - customers
      - customerKey: boolean

- customers
  - key
    - name: string

Example data

- projects
  - projectId1
    - name: "Cool project!",
    - customers
      - customerId1: true,
      - customerId2: true
  - projectId2
    - name: "Another cool project!",
    - customers
      - customerId2: true,
      - customerId3: true

- customers
  - customerId1
    - name: "John Smith"
  - customerId2
    - name: "John Doe"
  - customerId3
    - name: "John John"

So we're storing the customers' key in every projects' customers property.

Let's say we want to list every projects, but we also want to get the customers' real name as well, not just their id. Since firebase doesn't have joins we'll have to do this manually. Here's one way to do it:

this.projects = this.af.database.list(`projects`)
  .map(projects => {
    return projects.map(project => {
      project.customers.map(customer => {
        this.af.database.list(`customers`)
          .subscribe(c => {
            customer = c;
          });
      });
      return project;
    });
  });

The inner .subscribe could be changed to a simple .map if you want to get the data asynchronously (in this case use the async pipe in the template`).

易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!