问题
I have a recurrent pattern with the use of std::map.
I want to retrieve the value only when the key is present, otherwise I don't want to insert element. Currently I'm using count(key) or find(key) (which one is better? from the documentation the complexity seems to be the same) and if them returns a positive value that I access the map. However I would like to avoid the use of two operations on the map. Something like:
map<string, int> myMap;
int returnvalue;
boole result = myMap.get("key1",returnValue)
if(result){
\\ use returnValue
}
Reading the std::map documentation on cplusplus.com I found two functions for accessing map elements:
- at(): which throws an excpetion if the key is not present
- []: which insert a new value if the key is not present
None of them satisfy my necessity.
回答1:
Use map::find:
auto it = myMap.find(key);
if (it != myMap.end())
{
// use it->second
}
else
{
// not found
}
This part was easy. The harder problem is when you want to look up if an element exists and return it if it does, but otherwise insert a new element at that key, all without searching the map twice. For that you need to use lower_bound followed by hinted insertion.
回答2:
using count() for sure the key is exists
then uses find() to get the k/v pair
if (myMap.count(key))
{
auto it = myMap.find(key)
}
else
{
// not found
}
来源:https://stackoverflow.com/questions/19290780/stdmap-element-access-without-exception-and-without-insertion