Convert double to string quickly observing given precision

问题

I have a C++ program using SDL. During rendering, I need to draw some graphics components. I sometimes need to convert double variables, rounded to one decimal, to std::string.

For this, I'm currently using a ostringstream object and it works fine.

std::ostringstream ss;
ss << std::fixed << std::setprecision(1) << x;

However, I'm wondering if this way of converting variables is a good idea with regards to performance.

I've tried to round the double variables with std::to_string(std::round(x * 10) / 10)), but it didn't work -- I still got output like 2.500000000.

Is there another solution?
Does ostringstream incur a heavy cost?

回答1:

You can't specify the precision with std::to_string as it is a direct equivalent to printf with the parameter %f (if using double).

If you are concerned about not allocating each time the stream, you can do the following :

#include <iostream>
#include <sstream>
#include <iomanip>

std::string convertToString(const double & x, const int & precision = 1)
{
    static std::ostringstream ss;
    ss.str(""); // don't forget to empty the stream
    ss << std::fixed << std::setprecision(precision) << x;

    return ss.str();
}


int main() {
    double x = 2.50000;

    std::cout << convertToString(x, 5) << std::endl;
    std::cout << convertToString(x, 1) << std::endl;
    std::cout << convertToString(x, 3) << std::endl;

    return 0;
}

It outputs (see on Coliru) :

2.50000

2.5

2.500

I didn't check the performance though... but I think you could even do better by encapsulating this into a class (like only call std::fixed and std::precision once).

Otherwise, you could still use sprintf with the parameters that suits you.

Going a little further, with an encapsulating class that you could use as a static instance or a member of another class... as you wish (View on Coliru).

#include <iostream>
#include <sstream>
#include <iomanip>

class DoubleToString
{
public:
    DoubleToString(const unsigned int & precision = 1)
    {
        _ss << std::fixed;
        _ss << std::setprecision(precision);
    }

    std::string operator() (const double & x)
    {
        _ss.str("");
        _ss << x;
        return _ss.str();
    }

private:
    std::ostringstream _ss;

};


int main() {
    double x = 2.50000;

    DoubleToString converter;

    std::cout << converter(x) << std::endl;

    return 0;
}

Another solution without using ostringstream (View on Coliru) :

#include <iostream>
#include <string>
#include <memory>

std::string my_to_string(const double & value) {
  const int length = std::snprintf(nullptr, 0, "%.1f", value);

  std::unique_ptr<char[]> buf(new char[length + 1]);
  std::snprintf(buf.get(), length + 1, "%.1f", value);

  return std::string(buf.get());
}

int main(int argc, char * argv[])
{

    std::cout << my_to_string(argc) << std::endl;
    std::cout << my_to_string(2.5156) << std::endl;

}

来源：https://stackoverflow.com/questions/34744591/convert-double-to-string-quickly-observing-given-precision

标签

c++

sdl

ostringstream