问题
We have a bit of a SQL quandry. Say I have a results that look like this...
61E77D90-D53D-4E2E-A09E-9D6F012EB59C | A
61E77D90-D53D-4E2E-A09E-9D6F012EB59C | B
61E77D90-D53D-4E2E-A09E-9D6F012EB59C | C
61E77D90-D53D-4E2E-A09E-9D6F012EB59C | D
7ce953ca-a55b-4c55-a52c-9d6f012ea903 | E
7ce953ca-a55b-4c55-a52c-9d6f012ea903 | F
is there a way I can group these results within SQL to return as
61E77D90-D53D-4E2E-A09E-9D6F012EB59C | A B C D
7ce953ca-a55b-4c55-a52c-9d6f012ea903 | E F
Any ideas people?
Many thanks
Dave
回答1:
I prefer to define a custom user-defined aggregate. Here's an example of a UDA which will accomplish something very close to what you're asking.
Why use a user-defined aggregate instead of a nested SELECT? It's all about performance, and what you are willing to put up with. For a small amount of elements, you can most certainly get away with a nested SELECT, but for large "n", you'll notice that the query plan essentially runs the nested SELECT once for every row in the output list. This can be the kiss of death if you're talking about a large number of rows. With a UDA, it's possible to aggregate these values in a single pass.
The tradeoff, of course, is that the UDA requires you to use the CLR to deploy it, and that's something not a lot of people do often. In Oracle, this particular situation is a bit nicer as you can use PL/SQL directly to create your user-defined aggregate, but I digress...
回答2:
try this:
set nocount on;
declare @t table (id char(36), x char(1))
insert into @t (id, x)
select '61E77D90-D53D-4E2E-A09E-9D6F012EB59C' , 'A' union
select '61E77D90-D53D-4E2E-A09E-9D6F012EB59C' , 'B' union
select '61E77D90-D53D-4E2E-A09E-9D6F012EB59C' , 'C' union
select '61E77D90-D53D-4E2E-A09E-9D6F012EB59C' , 'D' union
select '7ce953ca-a55b-4c55-a52c-9d6f012ea903' , 'E' union
select '7ce953ca-a55b-4c55-a52c-9d6f012ea903' , 'F'
set nocount off
SELECT p1.id,
stuff(
(SELECT
' ' + x
FROM @t p2
WHERE p2.id=p1.id
ORDER BY id, x
FOR XML PATH('')
)
,1,1, ''
) AS YourValues
FROM @t p1
GROUP BY id
OUTPUT:
id YourValues
------------------------------------ --------------
61E77D90-D53D-4E2E-A09E-9D6F012EB59C A B C D
7ce953ca-a55b-4c55-a52c-9d6f012ea903 E F
(2 row(s) affected)
EDIT
based on OP's comment about this needing to run for an existing query, try this:
;WITH YourBugQuery AS
(
--replace this with your own query
select '61E77D90-D53D-4E2E-A09E-9D6F012EB59C' AS ColID , 'A' AS ColX
union select '61E77D90-D53D-4E2E-A09E-9D6F012EB59C' , 'B'
union select '61E77D90-D53D-4E2E-A09E-9D6F012EB59C' , 'C'
union select '61E77D90-D53D-4E2E-A09E-9D6F012EB59C' , 'D'
union select '7ce953ca-a55b-4c55-a52c-9d6f012ea903' , 'E'
union select '7ce953ca-a55b-4c55-a52c-9d6f012ea903' , 'F'
)
SELECT p1.ColID,
stuff(
(SELECT
' ' + ColX
FROM YourBugQuery p2
WHERE p2.ColID=p1.ColID
ORDER BY ColID, ColX
FOR XML PATH('')
)
,1,1, ''
) AS YourValues
FROM YourBugQuery p1
GROUP BY ColID
this has the same results set as displayed above.
回答3:
Another way of doing it is to use the FOR XML PATH option
SELECT
[ID],
(
SELECT
[Value] + ' '
FROM
[YourTable] [YourTable2]
WHERE
[YourTable2].[ID] = [YourTable].[ID]
ORDER BY
[Value]
FOR XML PATH('')
) [Values]
FROM
[YourTable]
GROUP BY
[YourTable].[ID]
来源:https://stackoverflow.com/questions/2828080/sql-2005-merge-concatenate-multiple-rows-to-one-column