format not a string literal and no format arguments [-Wformat-security]

核能气质少年 提交于 2019-12-12 14:32:37

问题


I am not sure what is causing this error

./lhapdf_wrap.cc: In function ‘void SWIG_Python_AddErrorMsg(const char*)’:
./lhapdf_wrap.cc:877:62: warning: too many arguments for format [-Wformat-extra-args]
     PyErr_Format(type, "%s", PyString_AsString(old_str), mesg);
                                                              ^
./lhapdf_wrap.cc:881:42: warning: format not a string literal and no format arguments [-Wformat-security]
     PyErr_Format(PyExc_RuntimeError, mesg);
                                          ^

The code is:

SWIGRUNTIME void
SWIG_Python_AddErrorMsg(const char* mesg)
{
  PyObject *type = 0;
  PyObject *value = 0;
  PyObject *traceback = 0;

  if (PyErr_Occurred()) PyErr_Fetch(&type, &value, &traceback);
  if (value) {
    PyObject *old_str = PyObject_Str(value);
    PyErr_Clear();
    Py_XINCREF(type);
    PyErr_Format(type, "%s %s", PyString_AsString(old_str), mesg);
    Py_DECREF(old_str);
    Py_DECREF(value);
  } else {
    PyErr_Format(PyExc_RuntimeError, mesg);
  }
}

I have looked into the string literal error but the %s is already present?


回答1:


Make the format string literal explicit:

printf("%s", str);

The same warning can be reproduced with the following snippet:

#include <stdio.h>

int main()
{
    char str[] = "hello";
    printf(str);
}

main.cpp:6:12: warning: format string is not a string literal (potentially insecure) 
[-Wformat-security]

The compiler cannot verify if str contains a %s.

The first warning has a mismatch instead: insufficient format specifiers (e.g. another %s) in the string literal, since two additional argument follow.



来源:https://stackoverflow.com/questions/26598085/format-not-a-string-literal-and-no-format-arguments-wformat-security

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