问题
I have a survfit
object. A summary survfit for my t=0:50
years of interest is easy enough.
summary(survfit, t=0:50)
It gives the survival at each t.
Is there a way to get the hazard for each t (in this case, the hazard from t-1 to t in each t=0:50)? I want to get the mean and confidence interval (or standard error) for the hazards relating to the Kaplan Meier curve.
This seems easy to do when a distribution is fit (eg. type="hazard"
in flexsurvreg
) but I can't figure out how to do this for a regular survfit object. Suggestions?
回答1:
It is a bit tricky since the hazard is an estimate of an instantaneous probability (and this is discrete data), but the basehaz
function might be of some help, but it only returns the cumulative hazard. So you would have still have to perform an extra step.
I have also had luck with the muhaz
function. From its documentation:
library(muhaz)
?muhaz
data(ovarian, package="survival")
attach(ovarian)
fit1 <- muhaz(futime, fustat)
plot(fit1)

I am not sure the best way to get at the 95% confidence interval, but bootstrapping might be one approach.
#Function to bootstrap hazard estimates
haz.bootstrap <- function(data,trial,min.time,max.time){
library(data.table)
data <- as.data.table(data)
data <- data[sample(1:nrow(data),nrow(data),replace=T)]
fit1 <- muhaz(data$futime, data$fustat,min.time=min.time,max.time=max.time)
result <- data.table(est.grid=fit1$est.grid,trial,haz.est=fit1$haz.est)
return(result)
}
#Re-run function to get 1000 estimates
haz.list <- lapply(1:1000,function(x) haz.bootstrap(data=ovarian,trial=x,min.time=0,max.time=744))
haz.table <- rbindlist(haz.list,fill=T)
#Calculate Mean,SD,upper and lower 95% confidence bands
plot.table <- haz.table[, .(Mean=mean(haz.est),SD=sd(haz.est)), by=est.grid]
plot.table[, u95 := Mean+1.96*SD]
plot.table[, l95 := Mean-1.96*SD]
#Plot graph
library(ggplot2)
p <- ggplot(data=plot.table)+geom_smooth(aes(x=est.grid,y=Mean))
p <- p+geom_smooth(aes(x=est.grid,y=u95),linetype="dashed")
p <- p+geom_smooth(aes(x=est.grid,y=l95),linetype="dashed")
p

回答2:
As a supplement to Mike's answer, one could model the number of events by a Poisson distribution instead of a Normal distribution. The hazard rate can then be calculated via a gamma distribution. The code would become:
library(muhaz)
library(data.table)
library(rGammaGamma)
data(ovarian, package="survival")
attach(ovarian)
fit1 <- muhaz(futime, fustat)
plot(fit1)
#Function to bootstrap hazard estimates
haz.bootstrap <- function(data,trial,min.time,max.time){
library(data.table)
data <- as.data.table(data)
data <- data[sample(1:nrow(data),nrow(data),replace=T)]
fit1 <- muhaz(data$futime, data$fustat,min.time=min.time,max.time=max.time)
result <- data.table(est.grid=fit1$est.grid,trial,haz.est=fit1$haz.est)
return(result)
}
#Re-run function to get 1000 estimates
haz.list <- lapply(1:1000,function(x) haz.bootstrap(data=ovarian,trial=x,min.time=0,max.time=744))
haz.table <- rbindlist(haz.list,fill=T)
#Calculate Mean, gamma parameters, upper and lower 95% confidence bands
plot.table <- haz.table[, .(Mean=mean(haz.est),
Shape = gammaMME(haz.est)["shape"],
Scale = gammaMME(haz.est)["scale"]), by=est.grid]
plot.table[, u95 := qgamma(0.95,shape = Shape + 1, scale = Scale)]
# The + 1 is due to the discrete character of the poisson distribution.
plot.table[, l95 := qgamma(0.05,shape = Shape, scale = Scale)]
#Plot graph
ggplot(data=plot.table) +
geom_line(aes(x=est.grid, y=Mean),col="blue") +
geom_ribbon(aes(x=est.grid, y=Mean, ymin=l95, ymax=u95),alpha=0.5, fill= "lightblue")

As can be seen the negative estimates for the lower bound of the hazard rate are now gone.
回答3:
As an additional supplement, we can improve the performance of the bootstrap function by slimming down the parameters inside.
data(ovarian, package="survival")
library(muhaz)
haz.bootstrap.v2 <- function(x) {
x <- x[sample(1:nrow(x), nrow(x), replace=TRUE), ]
muhaz(x$futime, x$fustat, min.time=0, max.time=744)
}
# bootstrap
boot <- replicate(1e3, haz.bootstrap.v2(ovarian))
There is a slight performance burst of approx. 15% (1e3 reps. as above).
Unit: seconds
expr min lq mean median uq max neval cld
version1 6.376984 6.501841 6.700725 6.552303 6.677898 8.027701 100 b
version2 5.443420 5.516658 5.686726 5.565615 5.674727 6.953493 100 a
We have thrown the aggregation out of the function and do it now after boostrapping.
# aggregate data.table
p <- cbind(est.grid=unlist(boot[2, ]), haz.est=unlist(boot[3, ]))
Then we'll go on like before.
# calculate Mean, gamma parameters
library(data.table)
p <- data.table(p)
library(rGammaGamma)
p <- p[, .(mean=mean(haz.est),
shape=gammaMME(haz.est)["shape"],
scale=gammaMME(haz.est)["scale"]), by=est.grid]
Note that two-sided CIs are calculated with 1 - alpha/2
!
# calculate CIs
# note: the + 1 is due to the discrete character of the poisson distribution:
p[, u95 := qgamma(0.975, shape=shape + 1, scale=scale)]
p[, l95 := qgamma(0.025, shape=shape, scale=scale)]
And eventually the plot:
library(ggplot2)
ggplot(data=p) +
geom_line(aes(x=est.grid, y=mean), col="blue") +
geom_line(aes(x=est.grid, y=u95), lty=2, col="blue") +
geom_line(aes(x=est.grid, y=l95), lty=2, col="blue") +
labs(title="Hazard Estimates", x="Analysis Time", y="Hazard Rate",
caption=expression(paste(italic("Note: "),
alpha, "=0.05"))) +
theme_bw()
来源:https://stackoverflow.com/questions/29728795/how-do-i-extract-hazards-from-survfit-in-r