问题
Suppose I have a data say:
Name | Marks
StudentA | 90
StudentB | 85
StudentC | 85
StudentD | 70
now StudentA will get 1st Rank, StudentB and StudentC will get 2nd Rank and Student D will get 4th Rank.
I know the basic rank computation if there are no duplicate weights, but how to handle if we encounter 2 similar weights as in this case there are two 85 marks which will share rank 2.
回答1:
Using Giorgos's fiddle...
SELECT name
, marks
, FIND_IN_SET(marks, (SELECT GROUP_CONCAT(marks ORDER BY marks DESC) FROM mytable)) rank
FROM mytable;
| Name | Marks | rank |
|----------|-------|------|
| StudentA | 90 | 1 |
| StudentB | 85 | 2 |
| StudentC | 85 | 2 |
| StudentD | 70 | 4 |
http://sqlfiddle.com/#!9/7cc30/6
or
SELECT name, marks, rank
FROM (SELECT name
, marks
, @prev := @curr
, @curr := marks
, @i:=@i+1 temp
, @rank := IF(@prev = @curr, @rank, @i) AS rank
FROM mytable
, ( SELECT @curr := null, @prev := null, @rank := 0, @i:=0) vars
ORDER
BY marks DESC,name
) x
ORDER
BY marks DESC,name
http://sqlfiddle.com/#!9/287e07/9
回答2:
In php you can implement it in the following way:
$data = [
[95, 0], [85, 0], [85, 0], [85, 0], [70, 0], [70, 0], [50, 0]
];
$rank = 0;
$previous = null;
$skippedRank = 0;
foreach ($data as &$item) {
if ($item[0] != $previous) {
$rank += $skippedRank+1;
$previous = $item[0];
$skippedRank = 0;
} else {
$skippedRank++;
}
$item[1] = $rank;
}
print_r($data);
where $item[0]
is weight and $item[1]
is rank.
回答3:
You can use an additional variable to hold the mark of the previous record:
SELECT Name, Marks,
@rnk := IF(@prevMark = Marks, @rnk,
IF(@prevMark := Marks, @rnk + 1, @rnk + 1)) AS rank
FROM mytable
CROSS JOIN (SELECT @rnk := 0, @prevMark := 0) AS vars
ORDER BY Marks DESC
Demo here
来源:https://stackoverflow.com/questions/39214022/how-to-rank-a-record-with-same-weight-in-mysql