Undefined variable error when calling a function from another snippet

问题

The following PHP page

<?php
$a = "World";

function say() {
    echo $a;
}
?>

Hello, <?php say(); ?>

fails with:

Undefined variable: a in test.php on line 5

Could someone explain me why, and what is the best way to fix this?

回答1:

you have to define variable as global inside the function

<?php
 $a = "World";

function say() {
global $a;
echo $a;
}
 say(); 
?>

来源：https://stackoverflow.com/questions/14301958/undefined-variable-error-when-calling-a-function-from-another-snippet