How to generate sql from template and param placeholder with JOOQ?

问题

I get the sql template like this with jOOQ 3.11.11.

DSLContext context = new DefaultDSLContext(conf);
Query query = context.select().from("table1").where(DSL.field("report_date").eq(DSL.param("bizdate")));
String sqlTemp = context.renderNamedParams(query);

I store the plain sql template.

select * from table1 where report_date = :bizdate

The param 'bizdate' is decided by realtime query.
So. How to generate the real sql

select * from table1 where report_date = '20190801'

with the stored sql template string and the realtime input date '20190801'.

回答1:

You can use this:

context.resultQuery(sqlTemp, DSL.param("bizdate", "20190801")).fetch();

See DSLContext.resultQuery(String, QueryPart...)

来源：https://stackoverflow.com/questions/57588198/how-to-generate-sql-from-template-and-param-placeholder-with-jooq