问题
My JQuery process.js
file is not able to parse JSP EL expression. I am just tyring to display a List object in my JSP. If I just use the ${students}
object it works correctly and displays all the students but if I try to display it using JQuery it just displays the ${students}
string as it is in the browser. I have disabled scripting in my web.xml
and using EL for displaying data.
Is there any other way to handle this?
Browser Output:
Hello World from JQuery!
From JSP:
[Student{id=1, name=Jack}, Student{id=2, name=Jill}]
From JQuery:
${students}
home.jsp
<%@page contentType="text/html" pageEncoding="UTF-8"%>
<!DOCTYPE html>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>JSP Page</title>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/2.1.3/jquery.min.js"></script>
<script src="js/process.js"></script>
</head>
<body>
<div id="mydiv"></div>
<h2>From JSP: <p/> ${students}</h2>
<h3>From JQuery: <div id="studentDiv"></div></h3>
</body>
</html>
process.js
$(document).ready(function () {
//static message
var msg = "Hello World from JQuery!";
$("#mydiv").text(msg);
//dynamic message
var students = '${students}';
$("#studentDiv").text(students);
});
HomePageController.java
@WebServlet(name = "HomePageController", urlPatterns = {"/homePageController.do"})
public class HomePageController extends BaseController {
private static final String VIEW_NAME = "/jsp/home.jsp";
@Override
public void processRequest(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
List<Student> students = getAllStudents();
request.setAttribute("students", students);
request.getServletContext().getRequestDispatcher(VIEW_NAME).forward(request, response);
}
private List<Student> getAllStudents() {
List<Student> students = new ArrayList<>();
Student student1 = new Student(1, "Jack");
Student student2 = new Student(2, "Jill");
students.add(student1);
students.add(student2);
System.out.println("students = " + students);
return students;
}
}
BaseController.java
public abstract class BaseController extends HttpServlet {
@Override
public void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
processRequest(request, response);
}
@Override
public void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
processRequest(request, response);
}
public abstract void processRequest(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException;
}
web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns="http://xmlns.jcp.org/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd"
version="3.1">
<!-- Disable scripting -->
<jsp-config>
<jsp-property-group>
<url-pattern>*.jsp</url-pattern>
<scripting-invalid>true</scripting-invalid>
</jsp-property-group>
</jsp-config>
<session-config>
<session-timeout>30</session-timeout>
</session-config>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
</web-app>
回答1:
EL expressions are evaluated by JspServlet
(*.jsp
) and FacesServlet
(*.xhtml
) only. However, .js
files are by default not processed by those servlets, but by container's builtin default servlet. This is not jQuery's fault. This is just your fault.
A quick trick is to add *.js
URL pattern to the JspServlet
mapping. After figuring out the name of the container's builtin JspServlet
, which is in Tomcat and clones jsp
, add the below entry to your webapp's web.xml
:
<servlet-mapping>
<servlet-name>jsp</servlet-name>
<url-pattern>*.js</url-pattern>
</servlet-mapping>
Alternatives are:
- Refactor it to webservice call and use
$.getJSON()
. - Print it as HTML5
data
attribute and use$.data()
. - Print it as an inline script variable in JSP before desired script is included.
来源:https://stackoverflow.com/questions/33151409/jquery-not-able-to-parse-jsp-el