问题
For the variable coefficients second order linear ODE
$x''(t)+\beta_1(t)x'(t)+\beta_0 x(t)=0$
I have the numerical values (in terms of vectors) for $\beta_1(t)$ and $\beta_0(t)$, does anyone know some R package to do that? And some simple examples to illustrate would be great as well.
I googled to find 'bvpSolve' can solve constant coefficients value.
回答1:
In order to use deSolve, you have to make your second-order ODE
x''(t) + \beta_1(t) x'(t) + \beta_0 x(t)=0
into a pair of coupled first-order ODEs:
x'(t) = y(t)
y'(t) = - \beta_1(t) y(t) - \beta_0 x(t)
Then it's straightforward:
gfun <- function(t,z,params) {
g <- with(as.list(c(z,params)),
{
beta0 <- sin(2*pi*t)
beta1 <- cos(2*pi*t)
c(x=y,
y= -beta1*y - beta0*x))
list(g,NULL)
}
library("deSolve")
run1 <- ode(c(x=1,y=1),times=0:40,func=gfun,parms=numeric(0))
I picked some initial conditions (x(0)=1, x'(0)=1) arbitrarily; you might also want to add parameters to the model (i.e. make parms something other than numeric(0))
PS if you're not happy doing the conversion to coupled first-order ODEs by hand, and want a package that will seamlessly handle second-order ODEs, then I don't know the answer ...
来源：https://stackoverflow.com/questions/15756058/solve-variable-coefficients-second-order-linear-ode