问题
I'm trying to pass the php variable $shareURL = "someURL"; from the parent page of test.php into the included file of commentTest.php. Is this possible? If yes, please help.
Parent File = Test.php
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
</head>
<body>
<?php
$shareURL = "someURL";
echo "$shareURL";
include "http://domainName.net/assets/includes/commentTest.php";
?>
</body>
</html>
PHP Included File = commentTest.php
<?PHP
echo "<div class='fb-comments' data-href='$shareURL' data-num-posts='5' data-width='100%'></div>";
?>
HTML Output Source
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
</head>
<body>
someURL<div class='fb-comments' data-href='' data-num-posts='5' data-width='100%'></div></body>
</html>
回答1:
Change your Test.php to this:
include "/assets/includes/commentTest.php";
回答2:
Thanks everyone!
Your comments and answers helped me find the solution I needed.
$root = dirname(__FILE__);
include "$root/assets/includes/commentTest.php";
Apparently my root is here /var/www/html instead of right after the TLD in the URL.
来源:https://stackoverflow.com/questions/48858279/how-use-a-php-variable-declared-in-the-parent-file-in-an-included-file