问题
I want to return a List which contains data related to the Age Distribution (Eg. For Age 0-9 there are 10 persons, for 10-19 there are 7 persons etc)
This is my query :-
public List<ReportHelper> GetAgeDistribution(int userId)
{
var itemList = (from item in this.ObjectContext.TreeMembers
where item.UserId == userId
group (DateTime.Now - (item.Birthdate ?? DateTime.Now)).Days/365.25
by ((DateTime.Now - (item.Birthdate ?? DateTime.Now)).Days / 365.25) / 9);
List<ReportHelper> list = new List<ReportHelper>();
foreach (var item in itemList)
list.Add(new ReportHelper { Data = item.Count(), Label = item.Key + "-" + (item.Key + 9) });
return list;
}
When I run this query I get dbarithmeticexpression exception :
DbArithmeticExpression arguments must have a numeric common type.
How do I solve this error? I know Entity Framework 4 is not able to translate my expression to plain old sql. How can I hint it what I am trying to do?
Thanks in advance :)
回答1:
Saeed is right; the best way to go here is to use the canonical DiffYears function through the EntityFunctions.DiffYears method.
In addition, the logic you have for dividing ages into the buckets [0 - 9] years, [10 - 19] years etc. seems incorrect; you should divide complete years by 10, not 9.
This query should work fine:
var itemList = from item in this.ObjectContext.TreeMembers
where item.UserId == userId
let age = EntityFunctions.DiffYears
(item.Birthdate, DateTime.Now) ?? 0
group item by age / 10 into ageGroup
select new
{
AgeInCompletedDecades = ageGroup.Key,
Count = ageGroup.Count()
};
回答2:
you can't do this in EF:
DateTime.Now - (item.Birthdate ?? DateTime.Now))....
you can use Entity canonical functions for this purpose.
In fact you can't do DateTime1 - DateTime2 in EF.
回答3:
My guess would be to change 365.25 to 365 (so it's an int like the Days property).
回答4:
What if you converted your dates to numerical values using the mydate.ToOADate() function? This function converts dates to a double value where the whole number portion of the double represents what day it is and the fractional part of the double represents a fractional day (i.e. time of day).
I don't know much about Entity arithmetic, but if the dates were doubles then it might not throw that exception - just a guess.
来源:https://stackoverflow.com/questions/5764768/how-do-i-get-age-distribution-list-by-grouping