Error in running a Python code from R with the package rPithon

问题

I would like to run this Python code from R:

>>> import nlmpy 
>>> nlm = nlmpy.mpd(nRow=50, nCol=50, h=0.75) 
>>> nlmpy.exportASCIIGrid("raster.asc", nlm)

Nlmpy is a Python package to build neutral landscape models. The example comes from the website

To run this Python code from R, I 'm trying to use the package rPithon. However, I obtain this error message:

if (pithon.available()) 
{ 
  nRow <- 50 
  nCol <- 50 
  h <- 0.75 

  # this file contains the definition of function concat 
  pithon.load("C:/Users/Anaconda2/Lib/site-packages/nlmpy/nlmpy.py") 
  pithon.call( "mpd", nRow, nCol, h) 

} else { 
  print("Unable to execute python") 
} 

Error in pithon.get("_r_call_return", instance.name = instname) : 
Couldn't retrieve variable: Traceback (most recent call last): 
File "C:/Users/Documents/R/win-library/3.3/rPithon/pythonwrapperscript.py", line 110, in <module> 
reallyReallyLongAndUnnecessaryPrefix.data = json.dumps([eval(reallyReallyLongAndUnnecessaryPrefix.argData)]) 
File "C:\Users\ANACON~1\lib\json\__init__.py", line 244, in dumps 
return _default_encoder.encode(obj) 
File "C:\Users\ANACON~1\lib\json\encoder.py", line 207, in encode 
chunks = self.iterencode(o, _one_shot=True) 
File "C:\Users\ANACON~1\lib\json\encoder.py", line 270, in iterencode 
return _iterencode(o, 0) 
File "C:\Users\ANACON~1\lib\json\encoder.py", line 184, in default 
raise TypeError(repr(o) + " is not JSON serializable") 
TypeError: array([[ 0.36534654,  0.31962481,  0.44229946, ...,  0.11513079, 
0.07156331,  0.00286971], [ 0.41534291,  0.41333479,  0.48118995, ...,  0.19203674, 
0.04192771,  0.03679473], [ 0.5188

Is this error caused by a syntax issue in my code ? I work with the Anaconda 4.2.0 platform for Windows which uses the Python 2.7 version.

回答1:

I haven't used the nlmpy package hence, I am not sure what would be your expected output. However, this code successfully communicates between R and Python.

There are two files,

nlmpyInR.R

command ="python"
path2script="path_to_your_pythoncode/nlmpyInPython.py"

nRow <-50 
nCol <-50 
h <- 0.75

# Build up args in a vector
args = c(nRow, nCol, h)

# Add path to script as first arg
allArgs = c(path2script, args)

Routput = system2(command, args=allArgs, stdout=TRUE)
#The command would be python nlmpyInPython.py 50 50 0.75

print(paste("The Output is:\n", Routput))

nlmpyInPython.py

import sys
import nlmpy 
#Getting the arguments from the command line call
nRow = sys.argv[1]
nCol = sys.argv[2]
h = sys.argv[3]

nlm = nlmpy.mpd(nRow, nCol, h) 
pyhtonOutput = nlmpy.exportASCIIGrid("raster.asc", nlm)
#Whatever you print will get stored in the R's output variable. 
print pyhtonOutput

回答2:

The cause of the error that you're getting is hinted at by the "is not JSON serializable" line. Your R code calls the mpd function with certain arguments, and that function itself will execute correctly. The rPithon library will then try to send the return value of the function back to R, and to do this it will try to create a JSON object that describes the return value.

This works well for integers, floating point values, arrays, etc, but not every kind of Python object can be converted to such a JSON representation. And because rPithon can't convert the return value of mpd this way, an error is generated.

You can still use rPithon to call the mpd function though. The following code creates a new Python function that performs two steps: first it calls the mpd function with the specified parameters, and then it exports the result to a file, of which the filename is also an argument. Using rPithon, the new function is then called from R. Because myFunction doesn't return anything, representing the return value in JSON format will not be a problem.

library("rPithon")

pythonCode = paste("import nlmpy.nlmpy as nlmpy",
                   "",
                   "def myFunction(nRow, nCol, h, fileName):",
                   "    nlm = nlmpy.mpd(nRow, nCol, h)",
                   "    nlmpy.exportASCIIGrid(fileName, nlm)", 
                   sep = "\n")
pithon.exec(pythonCode)

nRow <- 50 
nCol <- 50 
h <- 0.75 

pithon.call("myFunction", nRow, nCol, h, "outputraster.asc")

Here, the Python code defined as an R string, and executed using pithon.exec. You could also put that Python code in a separate file and use pithon.load to process the code so that the myFunction function is known.

来源：https://stackoverflow.com/questions/40667328/error-in-running-a-python-code-from-r-with-the-package-rpithon

标签

rpython