问题
I'm working an application of which only one instance must exist at any given time. There are several possibilities to accomplish this:
- Check running processes for one matching our EXE's name (unreliable)
- Find the main window (unreliable, and I don't always have a main window)
- Create a mutex with a unique name (GUID)
The mutex option seems to me the most reliable and elegant.
However, before my second instance terminates, I want to post a message to the already running instance. For this, I need a handle to the thread (or the process) that owns the mutex.
However, there seems to be no API function to get the creator/owner of a given mutex. Am I just overlooking it? Is there another way to get to this thread/process? Is there another way to go about this?
Update: This guy simply broadcast a message to all running processes. I guess that's possible, but I don't really like it...
回答1:
I don't think there is a trivial way to resolve the actual owner of a Mutex, but the process that owns it can create other secondary items whose lifetimes are tied to it. There are plenty of mechanisms that are suitable for calling back across-process without having a main window.
- Register an object in the COM Running Object Table. Clients that are unable to take ownership of the Mutex can lookup the owner via the ROT and call back to the owner. A File Moniker should be suitable for registration here.
- Create a chunk of shared memory containing location details for the owner process. From there, write into the buffer the process handle and thread handle of a thread that can receive windows messages, and then use PostThreadMessage() to send a notification. Any other competing process may open the shared memory for read-only to determine where to send a windows message.
- Listen in the owner process on a Socket or Named Pipe. Probably overkill and not a good match for your needs.
- Use a shared file with locking. I'm not fond of this because the owner will need to poll, and it won't gracefully handle N potential other processes that could be trying to contact the owner at the same time.
Here are reference links for the first two options.
- IRunningObjectTable @ MSDN , File Monikers @ MSDN
- Creating Named Shared Memory @ MSDN
回答2:
This should get you started on the original request to get a process that owns a mutex.
It's in C#, but the Win32 calls are the same.
class HandleInfo
{
[DllImport("ntdll.dll", CharSet = CharSet.Auto)]
public static extern uint NtQuerySystemInformation(int SystemInformationClass, IntPtr SystemInformation, int SystemInformationLength, out int ReturnLength);
[DllImport("kernel32.dll", SetLastError = true)]
internal static extern IntPtr VirtualAlloc(IntPtr address, uint numBytes, uint commitOrReserve, uint pageProtectionMode);
[DllImport("kernel32.dll", SetLastError=true)]
internal static extern bool VirtualFree(IntPtr address, uint numBytes, uint pageFreeMode);
[StructLayout(LayoutKind.Sequential)]
public struct SYSTEM_HANDLE_INFORMATION
{
public int ProcessId;
public byte ObjectTypeNumber;
public byte Flags; // 1 = PROTECT_FROM_CLOSE, 2 = INHERIT
public short Handle;
public int Object;
public int GrantedAccess;
}
static uint MEM_COMMIT = 0x1000;
static uint PAGE_READWRITE = 0x04;
static uint MEM_DECOMMIT = 0x4000;
static int SystemHandleInformation = 16;
static uint STATUS_INFO_LENGTH_MISMATCH = 0xC0000004;
public HandleInfo()
{
IntPtr memptr = VirtualAlloc(IntPtr.Zero, 100, MEM_COMMIT, PAGE_READWRITE);
int returnLength = 0;
bool success = false;
uint result = NtQuerySystemInformation(SystemHandleInformation, memptr, 100, out returnLength);
if (result == STATUS_INFO_LENGTH_MISMATCH)
{
success = VirtualFree(memptr, 0, MEM_DECOMMIT);
memptr = VirtualAlloc(IntPtr.Zero, (uint)(returnLength + 256), MEM_COMMIT, PAGE_READWRITE);
result = NtQuerySystemInformation(SystemHandleInformation, memptr, returnLength, out returnLength);
}
int handleCount = Marshal.ReadInt32(memptr);
SYSTEM_HANDLE_INFORMATION[] returnHandles = new SYSTEM_HANDLE_INFORMATION[handleCount];
using (StreamWriter sw = new StreamWriter(@"C:\NtQueryDbg.txt"))
{
sw.WriteLine("@ Offset\tProcess Id\tHandle Id\tHandleType");
for (int i = 0; i < handleCount; i++)
{
SYSTEM_HANDLE_INFORMATION thisHandle = (SYSTEM_HANDLE_INFORMATION)Marshal.PtrToStructure(
new IntPtr(memptr.ToInt32() + 4 + i * Marshal.SizeOf(typeof(SYSTEM_HANDLE_INFORMATION))),
typeof(SYSTEM_HANDLE_INFORMATION));
sw.WriteLine("{0}\t{1}\t{2}\t{3}", i.ToString(), thisHandle.ProcessId.ToString(), thisHandle.Handle.ToString(), thisHandle.ObjectTypeNumber.ToString());
}
}
success = VirtualFree(memptr, 0, MEM_DECOMMIT);
}
}
回答3:
I have never really understood the rational behind using a Mutex which has no signaling capability. I would instead create an event (using CreateEvent) which has the same properties as creating a mutex (i.e. with a name it can return that the object already existed) but you can set the event flag in the new process, as long as the original process is waiting on the event flag it can be notified when it needs to wake itself up.
回答4:
Create a shared memory area with the fixed name:
http://msdn.microsoft.com/en-us/library/aa366551%28VS.85%29.aspx
Then you can put any structure you like inside, including process id, HWND etc.
There's a portable option: create a socket on a port (with a fixed number) and wait (accept) on it. The second instance of the app will fail since the port is already taken. Then the second instance can connect to the socket of the primary instance and send any information desired.
I hope this helps...
回答5:
You could always do it the UNIX way and create a "pid" file, putting the process id of the currently running instance into that file. Then have the app delete the file when it exits.
When a new instance starts up it should verify that the process in the PID file is actually alive as well (in case the app exits abnormally and the file doesn't get deleted)
来源：https://stackoverflow.com/questions/1947312/win32-how-to-get-the-process-thread-that-owns-a-mutex