问题
I have a generic type that wraps a single primitive type to give it value equality semantics
public class ValueObject<T>
{
public T Value { get; }
public ValueObject(T value) => Value = value;
// various other equality members etc...
}
It is used like:
public class CustomerId : ValueObject<Guid>
{
public CustomerId(Guid value) : base(value) { }
}
public class EmailAddress : ValueObject<string>
{
public EmailAddress(string value) : base(value) { }
}
The issue is when serializing a type like:
public class Customer
{
public CustomerId Id { get; }
public EmailAddress Email { get; }
public Customer(CustomerId id, EmailAddress email)
{
Id = id;
Email = email;
}
}
Each object the inherits from ValueObject<T>
is wrapped in a Value
property (as expected). For example
var customerId = new CustomerId(Guid.NewGuid());
var emailAddress = new EmailAddress("some@email.com");
var customer = new Customer(customerId, emailAddress);
var customerAsJson = JsonConvert.SerializeObject(customer, Formatting.Indented, new JsonSerializerSettings
{
ContractResolver = new CamelCasePropertyNamesContractResolver()
})
Results in
{
"id": {
"value": "f5ce21a5-a0d1-4888-8d22-6f484794ac7c"
},
"email": {
"value": "some@email.com"
}
}
Is there a way to write a custom JsonConverter
so the the Value
property is excluded for types subclassing ValueObject<T>
so that the above example would output
{
"id": "f5ce21a5-a0d1-4888-8d22-6f484794ac7c",
"email": "some@email.com"
}
I would prefer to have a single JsonConverter
that can handle all ValueObject<T>
rather than having to define a separate JsonConverter
for each ValueObject<T>
subclass
My first attempt was
public class ValueObjectOfTConverter : JsonConverter
{
private static readonly Type ValueObjectGenericType = typeof(ValueObject<>);
private static readonly string ValuePropertyName = nameof(ValueObject<object>.Value);
public override bool CanConvert(Type objectType) =>
IsSubclassOfGenericType(objectType, ValueObjectGenericType);
public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
{
// converts "f5ce21a5-a0d1-4888-8d22-6f484794ac7c" => "value": "f5ce21a5-a0d1-4888-8d22-6f484794ac7c"
var existingJsonWrappedInValueProperty = new JObject(new JProperty(ValuePropertyName, JToken.Load(reader)));
return existingJsonWrappedInValueProperty.ToObject(objectType, serializer);
}
public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
{
// to implement
}
private static bool IsSubclassOfGenericType(Type typeToCheck, Type openGenericType)
{
while (typeToCheck != null && typeToCheck != typeof(object))
{
var cur = typeToCheck.IsGenericType ? typeToCheck.GetGenericTypeDefinition() : typeToCheck;
if (openGenericType == cur) return true;
typeToCheck = typeToCheck.BaseType;
}
return false;
}
}
回答1:
You can do this with a custom JsonConverter similar to the ones shown in Json.Net: Serialize/Deserialize property as a value, not as an object. However, since ValueObject<T>
does not have a non-generic method to get and set the Value
as an object, you will need to use reflection.
Here's one approach:
class ValueConverter : JsonConverter
{
static Type GetValueType(Type objectType)
{
return objectType
.BaseTypesAndSelf()
.Where(t => t.IsGenericType && t.GetGenericTypeDefinition() == typeof(ValueObject<>))
.Select(t => t.GetGenericArguments()[0])
.FirstOrDefault();
}
public override bool CanConvert(Type objectType)
{
return GetValueType(objectType) != null;
}
public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
{
// You need to decide whether a null JSON token results in a null ValueObject<T> or
// an allocated ValueObject<T> with a null Value.
if (reader.SkipComments().TokenType == JsonToken.Null)
return null;
var valueType = GetValueType(objectType);
var value = serializer.Deserialize(reader, valueType);
// Here we assume that every subclass of ValueObject<T> has a constructor with a single argument, of type T.
return Activator.CreateInstance(objectType, value);
}
const string ValuePropertyName = nameof(ValueObject<object>.Value);
public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
{
var contract = (JsonObjectContract)serializer.ContractResolver.ResolveContract(value.GetType());
var valueProperty = contract.Properties.Where(p => p.UnderlyingName == ValuePropertyName).Single();
// You can simplify this to .Single() if ValueObject<T> has no other properties:
// var valueProperty = contract.Properties.Single();
serializer.Serialize(writer, valueProperty.ValueProvider.GetValue(value));
}
}
public static partial class JsonExtensions
{
public static JsonReader SkipComments(this JsonReader reader)
{
while (reader.TokenType == JsonToken.Comment && reader.Read())
;
return reader;
}
}
public static class TypeExtensions
{
public static IEnumerable<Type> BaseTypesAndSelf(this Type type)
{
while (type != null)
{
yield return type;
type = type.BaseType;
}
}
}
You could then apply the converter directly to ValueType<T>
like so:
[JsonConverter(typeof(ValueConverter))]
public class ValueObject<T>
{
// Remainder unchanged
}
Or apply it in settings instead:
var settings = new JsonSerializerSettings
{
Converters = { new ValueConverter() },
ContractResolver = new CamelCasePropertyNamesContractResolver()
};
var customerAsJson = JsonConvert.SerializeObject(customer, Formatting.Indented, settings);
Working sample .Net fiddle #1 here.
Alternatively, you might consider adding a non-generic method to access the value as an object
, e.g. like so:
public interface IHasValue
{
object GetValue(); // A method rather than a property to ensure the non-generic value is never serialized directly.
}
public class ValueObject<T> : IHasValue
{
public T Value { get; }
public ValueObject(T value) => Value = value;
// various other equality members etc...
#region IHasValue Members
object IHasValue.GetValue() => Value;
#endregion
}
With this addition, WriteJson() becomes much simpler:
public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
{
serializer.Serialize(writer, ((IHasValue)value).GetValue());
}
Working sample .Net fiddle #2 here.
Notes:
ReadJson()
assumes that every subclass ofValue<T>
has a public constructor taking a single argument of typeT
.Applying the converter directly to
ValueType<T>
using [JsonConverter(typeof(ValueConverter))] will have slightly better performance, since CanConvert need never get called. See Performance Tips: JsonConverters for details.You need to decide how to handle a
null
JSON token. Should it result in a nullValueType<T>
, or an allocatedValueType<T>
with a nullValue
?In the second version of
ValueType<T>
I implementedIHasValue.GetValue()
explicitly to discourage its use in cases where an instance ofValueType<T>
is used in statically typed code.If you really only want to apply the converter to types subclassing
ValueObject<T>
and notValueObject<T>
itself, inGetValueType(Type objectType)
add a call to.Skip(1)
:static Type GetValueType(Type objectType) { return objectType .BaseTypesAndSelf() .Skip(1) // Do not apply the converter to ValueObject<T> when not subclassed .Where(t => t.IsGenericType && t.GetGenericTypeDefinition() == typeof(ValueObject<>)) .Select(t => t.GetGenericArguments()[0]) .FirstOrDefault(); }
And then apply the converter in
JsonSerializerSettings.Converters
rather than directly toValueObject<T>
.
来源:https://stackoverflow.com/questions/50313978/json-net-serialize-generic-type-wrapper-without-property-name