Javascript variable with leading zeroes

问题

Javascript behaves differently with values having leading zeroes. alert(b) - prints different value.

var a = 67116;
var b = 00015;
alert(a);
alert(b);

I am more interested to know What conversion is applied here by javascript inside alert(b) ? (If i have them in double quotes. They work fine.)

回答1:

Since js is weakly typed it thinks

var b = 00015

is an octal number

see this question for solution

回答2:

A leading 0 makes the value an octal literal, so the value you put will be interpreted as a base 8 integer.

In other words, 015 will be equivalent to parseInt('15', 8).

回答3:

As the other answers said, the leading zeroes make the number an octal literal. The decimal representation of the octal "15" is "13".

Note that there is no reason to use leading zeroes on number literals unless you really really want them to be interpreted as octals. I mean, don't use var b = 00015. If you're getting that value from user input, then it will be a string (i.e. "00015"), and you can convert to a decimal number with parseInt:

var b = "00015"; // or var b = document.getElementById('some_input').value
var numB = parseInt(b, 10); // 15

来源：https://stackoverflow.com/questions/17114258/javascript-variable-with-leading-zeroes