Is there a way to wrap an await/async try/catch block to every function?

夙愿已清 提交于 2019-11-27 01:53:11

Yes, you can easily write such a wrapper for asynchronous functions as well - just use async/await:

function wrapper(f) {
    return async function() {
//         ^^^^^
        try {
            return await f.apply(this, arguments);
//                 ^^^^^
        } catch(e) {
            customErrorHandler(e)
        }
    }
}

Or you use promises directly, like in this example that is more tailored to express (especially with the number of parameters):

function promiseWrapper(fn) {
    return (req, res, next) => {
         fn(req, res).catch(next);
    };
}

A similar answer here hope can help you

const sthError = () => Promise.reject('sth error');

const test = opts => {
  return (async () => {

    // do sth
    await sthError();
    return 'ok';

  })().catch(err => {
    console.error(err); // error will be catched there 
  });
};

test().then(ret => {
  console.log(ret);
});
易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!