问题
I was following a tutorial found here: https://www.linkedin.com/pulse/prepare-your-raspberry-pi-work-aws-iot-kay-lerch
I have not even begun the internet part of it as I was having issues with the circuit. I wired my circuit just like it is shown in this diagram below using my raspberry pi 3.
I then wrote the following python script as shown in the tutorial.
import RPi.GPIO as gpio
gpio.setmode(gpio.BOARD)
gpio.setup(7, gpio.IN, pull_up_down=gpio.PUD_DOWN)
def on_pushdown(channel):
print "Button Pushed."
while(True):
gpio.add_event_detect(7, gpio.RISING, callback=on_pushdown, bouncetime=200)
gpio.cleanup()
This should print out "Button Pushed" when I push the button but I get the following runtime error:
Traceback (most recent call last):
File "button.py", line 10, in <module>
gpio.add_event_detect(7, gpio.RISING, callback=on_pushdown, bouncetime=200)
RuntimeError: Conflicting edge detection already enabled for this GPIO channel
I have RPi.GPIO version 0.6.2 which is the latest version at the time o fthis post. I would appreciate any help that anyone can provide.
回答1:
The code you have is adding an event detection callback constantly (in the while(True) loop). What you want is to add the event detection callback once and then wait for an edge.
This page has a good example you might want to go through.
Alternatively, you could try something like:
import RPi.GPIO as gpio
gpio.setmode(gpio.BOARD)
gpio.setup(7, gpio.IN, pull_up_down=gpio.PUD_DOWN)
def on_pushdown(channel):
print "Button Pushed."
# only add the detection call once!
gpio.add_event_detect(7, gpio.RISING, callback=on_pushdown, bouncetime=200)
while(True):
try:
# do any other processing, while waiting for the edge detection
sleep(1) # sleep 1 sec
finally:
gpio.cleanup()
回答2:
Doddie's answer has the problem that the program exits after the first button press. Since the author mentioned an eternal loop, I would like to propose the following:
#!/usr/bin/python3
import RPi.GPIO as gpio
import time
pin = 7
def on_pushdown(channel):
print "Button Pushed."
try:
# Setting GPIO layout
gpio.setmode(gpio.BOARD)
# Set pin as input pin pulled down to GND
gpio.setup(pin, gpio.IN, pull_up_down=gpio.PUD_DOWN)
while True:
if not 'event' in locals():
event = gpio.add_event_detect(pin, gpio.RISING, callback=on_pushdown, bouncetime=200)
else:
time.sleep(1)
finally:
gpio.cleanup()
If the button is pressed and an event is detected, the variable event is being deleted. Hence, the add_event_detect-function is not called twice in a row.
Additionally two things:
- Depending on your setup, I would use a pull-up resistor. A pull-down setup is more prone to noise and an induction flank from somewhere might be interpreted as a button press.
- Although this is not best practice: If your setup is really small (like inside the RPi case) and you don't accidentally set
gpio.OUTand you just have a push button, you might consider to just take the build-in pull-up resistor and directly connect the push button to GND:GND --/ -- GPIO.IN(and then detect forgpio.FALLING).
来源:https://stackoverflow.com/questions/38125047/raspberry-pi-runtimeerror-conflicting-edge-detection-already-enabled-for-this-g