Formatting python docstrings for dicts

自闭症网瘾萝莉.ら 提交于 2019-12-10 01:25:28

问题


What's the recommended way of adding a docstring for a dictionary parameter? I can see multiple line docstring examples here.

I need to document the input arguments to a function in the docstring. If it's a simple variable, I can use something like:

 def func2(a=x, b = y):
 """ fun2 takes two integers 

 Keyword arguments:
 a -- refers to age (default 18)
 b -- refers to experience (default 0)
 """

If we have dict passed as input argument to function:

 def func3(**kwargs):
     """ takes dictionary as input

      <Here how to explain them - Is it like?> 
      kwargs['key1'] -- takes value1

      <or simply>
      key1 -- takes value1
      """

回答1:


I generally use the Google docstring style, so a dictionary parameter would look like:

def func(a_dict):
    """Some function to do something to a dictionary.

    Args:
      a_dict (dict of str: int): Some mapping, I guess?

    """
    ...

A function that takes **kwargs (note: this is not quite the same as having a dictionary parameter), would look like:

def func(**kwargs):
    """Some function to do stuff to arbitrary keyword arguments.

    Args:
      **kwargs: Arbitrary keyword arguments.

    """
    ...

If there are specific parameters that should be present (e.g. your key1), they should be separate, not rolled into **kwargs.


In Python 3.x, you can also use function annotations:

def func(a_dict: dict):
    """Some function to do something to a dictionary."""
    ...

From Python 3.5, you can be even more explicit using typing:

from typing import Mapping

def func(a_dict: Mapping[str, int]):
    """Some function to do something to a dictionary."""
    ...


来源:https://stackoverflow.com/questions/26712533/formatting-python-docstrings-for-dicts

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