问题
My table VENDORBRANCH has composite keys: "vendorCode" and "vendorBranchCode" which I have defined using the @Id annotation and using @IdClass. The field "vendorCode" is referenced as a foreign key in VENDORCRTERMS class. I'm using postgresql db. Right now my sql query in the service implimentation looks like this but i want to include composite keys in the query:
Query<?> query = session.createQuery("from VENDORBRANCH where vendorCode = ?");
query.setParameter(0, mf01_vendorCode);
I'm very new to hibernate so tried a few options for the select query but I'm not sure if it's correct to do it this way. So, what would be the best select statement to use for a composite key??
VENDORBRANCH class:
import java.io.Serializable;
import java.util.Date;
import javax.persistence.Embeddable;
import javax.persistence.EmbeddedId;
import javax.persistence.Entity;
import javax.persistence.Id;
import javax.persistence.IdClass;
import javax.persistence.JoinColumn;
import javax.persistence.ManyToOne;
import com.parkson.poMain.backend.data.VENDORBRANCH.VBpk;
@SuppressWarnings("serial")
@Entity
@IdClass(VBpk.class)
public class VENDORBRANCH implements Serializable {
@Id
private String vendorCode;
@Id
private String vendorBranchCode;
//getters and setters
// inner class defined for primary key(composite keys)
public static class VBpk implements Serializable {
protected String vendorCode;
protected String vendorBranchCode;
public String getvendorCode() {
return vendorCode;
}
public void vendorCode(String vendorCode) {
this.vendorCode = vendorCode;
}
public String vendorBranchCode() {
return vendorBranchCode;
}
public void vendorBranchCode(String vendorBranchCode) {
this.vendorBranchCode = vendorBranchCode;
}
public VBpk(){}
public VBpk(String vendorCode,String vendorBranchCode){
this.vendorCode = vendorCode;
this.vendorBranchCode = vendorBranchCode;
}
@Override
public int hashCode() {
final int prime = 31;
int result = 1;
result = prime * result + ((vendorBranchCode == null) ? 0 : vendorBranchCode.hashCode());
result = prime * result + ((vendorCode == null) ? 0 : vendorCode.hashCode());
return result;
}
@Override
public boolean equals(Object obj) {
if (this == obj)
return true;
if (obj == null)
return false;
if (getClass() != obj.getClass())
return false;
VBpk other = (VBpk) obj;
if (vendorBranchCode == null) {
if (other.vendorBranchCode != null)
return false;
} else if (!vendorBranchCode.equals(other.vendorBranchCode))
return false;
if (vendorCode == null) {
if (other.vendorCode != null)
return false;
} else if (!vendorCode.equals(other.vendorCode))
return false;
return true;
}
}
}
My other class: VENDORCRTERMS
import java.io.Serializable;
import java.util.Date;
import javax.persistence.Entity;
import javax.persistence.Id;
import javax.persistence.JoinColumn;
import javax.persistence.ManyToOne;
@SuppressWarnings("serial")
@Entity
public class VENDORCRTERMS implements Serializable {
@Id
private String vcrId ;
//This is the foreign key referenced from **VENDORBRANCH class**
@ManyToOne
@JoinColumns( {
@JoinColumn(name="vendorcode", nullable = false),
@JoinColumn(name="vendorBranchCode", nullable = false)} )
private VENDORBRANCH vendorbranch_vendorcode = new VENDORBRANCH();
// foreign key referenced from a different class
@ManyToOne
@JoinColumn(name= "creditterms_credittermscode" , nullable = false)
private CREDITTERMS creditterms_credittermscode = new CREDITTERMS();
//getters and setters
}
回答1:
VENDORBRANCH
has defined a composite primary key but in VENDORCRTERMS
you only use on @JoinColumn
for the reference. This is how the mapping should look like in your case:
@ManyToOne
@JoinColumns( {
@JoinColumn(name="vendorCode", referencedColumnName="vendorCode"),
@JoinColumn(name="vendorBranchCode", referencedColumnName="vendorBranchCode")
} )
private VENDORBRANCH vendorbranch_vendorcode
回答2:
The reason is: VENDORCRTERMS
class is confused because he observed that there are two @id
s in VENDORBRANCH
. I have a solution for you. What if you make the vendorCode
and vendorBranchCode
as unique key
as well as keeping only one primary key.
@Id
private String vendorCode;
I think this will satisfy your demand.
来源:https://stackoverflow.com/questions/44178725/composite-key-join-columns