How do I get the filepath for a class in Python?

问题

Given a class C in Python, how can I determine which file the class was defined in? I need something that can work from either the class C, or from an instance off C.

The reason I am doing this, is because I am generally a fan off putting files that belong together in the same folder. I want to create a class that uses a Django template to render itself as HTML. The base implementation should infer the filename for the template based on the filename that the class is defined in.

Say I put a class LocationArtifact in the file "base/artifacts.py", then I want the default behaviour to be that the template name is "base/LocationArtifact.html".

回答1:

You can use the inspect module, like this:

import inspect
inspect.getfile(C.__class__)

回答2:

try:

import sys, os
os.path.abspath(sys.modules[LocationArtifact.__module__].__file__)

回答3:

This is the wrong approach for Django and really forcing things.

The typical Django app pattern is:

• /project
  • /appname
    • models.py
    • views.py
    • /templates
      • index.html
      • etc.

来源：https://stackoverflow.com/questions/697320/how-do-i-get-the-filepath-for-a-class-in-python