laravel insert a new row that has a key from another table and a null columns

问题

This is my restaurant table:

the restaurant table has a adminID field . and this is the admin table:

I have a form that has the values of both the restaurant and the admin,

This is Admin model:

class Admin  extends Eloquent implements UserInterface, RemindableInterface {

    use UserTrait, RemindableTrait;

    public function restaurant(){
        return $this->belongsTo('Restaurant', 'ID');
    }

This is Restaurant model:

class Restaurant extends Eloquent implements UserInterface, RemindableInterface {

    use UserTrait, RemindableTrait;

    public function admin(){
        return $this->hasOne('Admin', 'adminID');
    }

This is the RestaurantsController for storing a new restaurant

$input = Input::all();
        $validation = Validator::make($input, Admin::$rules);
        if($validation->passes()){
            $validation = Validator::make($input, Restaurant::$rules);
            if ($validation->passes())
            {
                $admin = Admin::create(Input::only('username', 'password', 'mobileNumber', 'firstName', 'lastName'));

as you see now I have the $admin variable,

My Question

what is the statmnet that I need to insert a new restaurant

please note that I can take the adminID from $admin->id
please note that the restaurant has a null columns like logo and addressManualID

回答1:

At first, you don't need to implement UserInterface and RemindableInterface and and also don't use use UserTrait, RemindableTraitto create all of your models but only the User model if you have a User model for user authentication (log in/out). If the Admin model is being used as a replacement of the User model then you need to implement those interfaces and also need to use those traits as well. Also you need to explicitly declare the protected $table property to assign the table name which is being used for Admin model (If you are not using User model) and also you need to change some settings in app/config/auth.php file as given below:

'model' => 'Admin',

'table' => 'admins', // Could be anything else, same as protected $table property

Then try following to save the the related model when creating Admin:

//...
if ($validation->passes()) {
    $admin = Admin::create( Input::only('username', ...) );
    $restaurent = new Restaurant(Input::only(...));
    $admin->restaurant()->save($restaurent);
}

回答2:

You will want to use associate() method.

$restaurant = Restaurant::find(10);
$restaurant->admin()->associate($admin);
$restaurant->save();

Reference: http://laravel.com/docs/eloquent#inserting-related-models

来源：https://stackoverflow.com/questions/24274903/laravel-insert-a-new-row-that-has-a-key-from-another-table-and-a-null-columns

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