Generate a Swagger file for certain endpoints from another Swagger or OpenAPI file

问题

Having one big Swagger/OpenAPI YAML specification, how can I safely extract certain API endpoints and generate a new .yaml for them exclusively?

It's easy to identify API endpoints from a certain level (like defined with one indent or more):

paths:
  /users:
    ...
      - $ref: '#/requests/getUser'
  /repos:
    ...
requests:
  getUser:
    ...

I'd just copy all sections, except paths, into a new specs file. And then I'd copy certain paths subsections like /users: based on indents. In Python, with a regex.

But is this direct method safe for the specs?

回答1:

Swagger Inspector lets you make API calls and then create the definition file from them (letting you pick just a subset of calls like you want). See inspector.swagger.io - it's UI-based, but might save you some time.

来源：https://stackoverflow.com/questions/47590562/generate-a-swagger-file-for-certain-endpoints-from-another-swagger-or-openapi-fi