Pytest - python testing with asyncio

问题

Is it possible to return execution to event loop from a function. And as soon Task will be completed return to the function and continue execution?

Im trying to use pytest-asyncio plugin

Example:

@pytest.mark.asyncio
async def test_async1(event_loop):
    print('start 1')
    res = event_loop.create_task(
        send_async_request("http://test.com", limit=1000))) # here I need to return execution to event loop and continue only after getting response from send_async_request function 
    print('end1',res)



@pytest.mark.asyncio
async def test_async2(event_loop):
    print('start 2')
    res = event_loop.create_task(
        send_async_request("http://test2", limit=1000))) # here I need to return execution to event loop and continue only after getting response from send_async_request function
    print('end2', res)

send_async_request- aiohttp:

@asyncio.coroutine
def send_async_request(url, method='GET'):
    with aiohttp.ClientSession() as session:
        resp = yield from session.get(url, timeout=60)
        if resp.status == 200:
            return resp.status, response
        else:
            return resp.status, False

回答1:

When your tests are marked with pytest.mark.asyncio, they become coroutines so you can use the await syntax:

@pytest.mark.asyncio
async def test_sleep(event_loop):
    result = await asyncio.sleep(1, result=3, loop=event_loop)
    assert result == 3

---

EDIT: Another example, with multiple sleep operations:

@pytest.mark.asyncio
async def test_multiple_sleep(event_loop):
    tasks = [event_loop.create_task(asyncio.sleep(1, result=x))
             for x in range(10)]
    results = await asyncio.gather(*tasks)
    assert results == list(range(10))

来源：https://stackoverflow.com/questions/45410434/pytest-python-testing-with-asyncio