问题
I have a table data_summaries. It has such columns as item_id INT(11), user_grouping TEXT and value DECIMAL(10,2).
If I try to make a query that groups the results by user_grouping and orders them by the AVG of value, that fails:
SELECT user_grouping, AVG(value) AS avg_value, SUM(value) AS sum_value
FROM data_summaries
GROUP BY user_grouping
ORDER BY avg_value
+---------------+-----------+-----------+
| user_grouping | avg_value | sum_value |
+---------------+-----------+-----------+
| London | 50.609733 | 18978.65 |
| Paris | 50.791733 | 19046.90 |
| New York | 51.500400 | 2575.02 |
| NULL | 49.775627 | 18665.86 |
+---------------+-----------+-----------+
The ORDER BY clause does seem to be doing something as it does change the order:
SELECT user_grouping, AVG(value) AS avg_value, SUM(value) AS sum_value
FROM data_summaries
GROUP BY user_grouping
+---------------+-----------+-----------+
| user_grouping | avg_value | sum_value |
+---------------+-----------+-----------+
| NULL | 49.775627 | 18665.86 |
| New York | 51.500400 | 2575.02 |
| London | 50.609733 | 18978.65 |
| Paris | 50.791733 | 19046.90 |
+---------------+-----------+-----------+
On the other hand, ordering by the SUM of value works as expected:
SELECT user_grouping, AVG(value) AS avg_value, SUM(value) AS sum_value
FROM data_summaries
GROUP BY user_grouping
ORDER BY sum_value
+---------------+-----------+-----------+
| user_grouping | avg_value | sum_value |
+---------------+-----------+-----------+
| New York | 51.500400 | 2575.02 |
| NULL | 49.775627 | 18665.86 |
| London | 50.609733 | 18978.65 |
| Paris | 50.791733 | 19046.90 |
+---------------+-----------+-----------+
If I group by item_id instead, then ordering by the AVG works:
SELECT item_id, AVG(value) AS avg_value, SUM(value) AS sum_value
FROM data_summaries
GROUP BY item_id
+---------+-----------+-----------+
| item_id | avg_value | sum_value |
+---------+-----------+-----------+
| 4 | 49.318225 | 11392.51 |
| 1 | 49.737835 | 11489.44 |
| 2 | 50.420606 | 11647.16 |
| 6 | 51.024242 | 11786.60 |
| 5 | 51.456537 | 11886.46 |
| 3 | 53.213000 | 1064.26 |
+---------+-----------+-----------+
How would I need to change the first query to get it ordered by the average?
回答1:
That is a MySQL bug, see Unexpected order for grouped query, that involves avg() in combination with grouping by a text-column. It is still open in MySQL 5.7.15.
As a workaround, you can change your datatype to e.g. varchar. If you don't need indexes to speed it up, casting should work too:
SELECT cast(user_grouping as char(200)), AVG(value) AS avg_value, SUM(value) AS sum_value
FROM data_summaries
GROUP BY cast(user_grouping as char(200))
ORDER BY avg_value
Update:
The bug is fixed in MySQL 5.7.17:
Queries that were grouped on a column of a BLOB-based type, and that were ordered on the result of the AVG(), VAR_POP(), or STDDEV_POP() aggregate function, returned results in the wrong order if InnoDB temporary tables were used. (Bug #22275357, Bug #79366)
来源：https://stackoverflow.com/questions/39719785/can-not-order-by-an-avg-value-with-certain-group-by-criteria-in-mysql