Triple DES encryption | 易学教程

问题

Please note that the issue I am having here is with the key size. At first, based on the comments included in the below code, I figured that my key needed to be 24 bytes (192 bits). This didn't work so I gave 16, 32, and 8 byte keys a shot - nothing seems to be working. By "not working" I mean that after my text has been encrypted and decrypted it does not hold the same value as my original text.

Example:

Original Text: 'Example test this should work '

Encrypted Text: ¸¹pÕô6

Decrypted Text: 'Example '

Here are the two functions I am using (Encrypt / Decrypt functions). Also I will include how I am calling each function.

        // 168-bit (three-key) 3DES (Triple-DES) encrypt a single 8-byte block (ECB mode)
        // plain-text should be 8-bytes, key should be 24 bytes.
        public byte[] TripleDesEncryptOneBlock(byte[] plainText, byte[] key)
        {
            // Create a new 3DES key.
            TripleDESCryptoServiceProvider des = new TripleDESCryptoServiceProvider();

            // Set the KeySize = 192 for 168-bit DES encryption.
            // The msb of each byte is a parity bit, so the key length is actually 168 bits.

            des.KeySize = 192;
            des.Key = key;
            des.Mode = CipherMode.ECB;
            des.Padding = PaddingMode.None;

            ICryptoTransform ic = des.CreateEncryptor();

            byte[] enc = ic.TransformFinalBlock(plainText, 0, 8);

            return enc;
        }

        public byte[] TripleDesDecryptBlock(byte[] plainText, byte[] key)
        {
            // Create a new 3DES key.
            TripleDESCryptoServiceProvider des = new TripleDESCryptoServiceProvider();

            // Set the KeySize = 192 for 168-bit DES encryption.
            // The msb of each byte is a parity bit, so the key length is actually 168 bits.
            des.KeySize = 192;
            des.Key = key;
            des.Mode = CipherMode.ECB;
            des.Padding = PaddingMode.None;

            ICryptoTransform ic = des.CreateDecryptor();

            byte[] dec = ic.TransformFinalBlock(plainText, 0, 8);

            return dec;
        }

// Encrypt Text
textBox5.Text = ByteToString(TripleDesEncryptOneBlock(StringToByte(textBox5.Text), StringToByte("1 2 3 4 5 6 7 8 9 1 1 2 ")));

// Decrypt Text
textBox5.Text = ByteToString(TripleDesDecryptBlock(StringToByte(textBox5.Text), StringToByte("1 2 3 4 5 6 7 8 9 1 1 2 ")));

Thank you for any help,

Evan

回答1:

The clue is in the name of the function you're using: TripleDesEncryptOneBlock

This method only encrypts one block of the input string (8 bytes or 64 bits). To encrypt the entire string you need to chain multiple calls to this method.

回答2:

Use this:

byte[] enc = ic.TransformFinalBlock(plainText, 0, plainText.Length);

I hope it will encrypt/decrypt your whole string. Also you will need not to call this method multiple times

来源：https://stackoverflow.com/questions/6990286/triple-des-encryption

标签

encryption

des