问题
The relevant Redux state consists of an array of objects representing layers.
Example:
let state = [
{ id: 1 }, { id: 2 }, { id: 3 }
]
I have a Redux action called moveLayerIndex:
actions.js
export const moveLayerIndex = (id, destinationIndex) => ({
type: MOVE_LAYER_INDEX,
id,
destinationIndex
})
I would like the reducer to handle the action by swapping the position of the elements in the array.
reducers/layers.js
const layers = (state=[], action) => {
switch(action.type) {
case 'MOVE_LAYER_INDEX':
/* What should I put here to make the below test pass */
default:
return state
}
}
The test verifies that a the Redux reducer swaps an array's elements in immutable fashion.
Deep-freeze is used to check the initial state is not mutated in any way.
How do I make this test pass?
test/reducers/index.js
import { expect } from 'chai'
import deepFreeze from'deep-freeze'
const id=1
const destinationIndex=1
it('move position of layer', () => {
const action = actions.moveLayerIndex(id, destinationIndex)
const initialState = [
{
id: 1
},
{
id: 2
},
{
id: 3
}
]
const expectedState = [
{
id: 2
},
{
id: 1
},
{
id: 3
}
]
deepFreeze(initialState)
expect(layers(initialState, action)).to.eql(expectedState)
})
回答1:
One of the key ideas of immutable updates is that while you should never directly modify the original items, it's okay to make a copy and mutate the copy before returning it.
With that in mind, this function should do what you want:
function immutablySwapItems(items, firstIndex, secondIndex) {
// Constant reference - we can still modify the array itself
const results= items.slice();
const firstItem = items[firstIndex];
results[firstIndex] = items[secondIndex];
results[secondIndex] = firstItem;
return results;
}
I wrote a section for the Redux docs called Structuring Reducers - Immutable Update Patterns which gives examples of some related ways to update data.
回答2:
You could use map function to make a swap:
function immutablySwapItems(items, firstIndex, secondIndex) {
return items.map(function(element, index) {
if (index === firstIndex) return items[secondIndex];
else if (index === secondIndex) return items[firstIndex];
else return element;
}
}
In ES2015 style:
const immutablySwapItems = (items, firstIndex, secondIndex) =>
items.map(
(element, index) =>
index === firstIndex
? items[secondIndex]
: index === secondIndex
? items[firstIndex]
: element
)
来源:https://stackoverflow.com/questions/41127548/how-do-i-swap-array-elements-in-an-immutable-fashion-within-a-redux-reducer