For loop using more than one list in Python [duplicate]

问题

This question already has answers here:

Loop over 2 lists, repeating the shortest until end of longest (2 answers)

How can I infinitely loop an iterator in Python, via a generator or other? (3 answers)

Closed 13 days ago.

I'm looking for solution to my problem. At the moment I have two list of elements:

column_width = ["3", "3", "6", "8", "4", "4", "4", "4"]
fade = ["100", "200", "300"]

What I want to achieve is to create for loop which wil give me following output:

column-3-fade-100
column-3-fade-200
column-6-fade-300
column-8-fade-100
column-4-fade-200
...

Nested for loop doen't work for me:

for i in fade:
    for c in column_width_a:
        print("column-{0}-fade-{1}".format(c, i))

Is there any other way to generate this output?

回答1:

This is one approach using itertools.cycle.

Ex:

from itertools import cycle

column_width = ["3", "3", "6", "8", "4", "4", "4", "4"]
fade = cycle(["100", "200", "300"])

for i in column_width:
    print("column-{}-fade-{}".format(i, next(fade)))

Output:

column-3-fade-100
column-3-fade-200
column-6-fade-300
column-8-fade-100
column-4-fade-200
column-4-fade-300
column-4-fade-100
column-4-fade-200

回答2:

Try:

from itertools import cycle
print('\n'.join("column-{}-fade-{}".format(x, y) for x, y in zip(column_width, cycle(fade))))

来源：https://stackoverflow.com/questions/58971397/for-loop-using-more-than-one-list-in-python