问题
Is it possible to replace the BOOST_FOREACH
in this example with a "pure" C++11 equivalent?
#include <map>
#include <functional>
#include <boost/foreach.hpp>
#include <iostream>
int main() {
std::map<int, std::string> map = {std::make_pair(1,"one"), std::make_pair(2,"two")};
int k;
std::string v;
BOOST_FOREACH(std::tie(k, v), map) {
std::cout << "k=" << k << " - " << v << std::endl;
}
}
The key feature being keeping the key/value pair in the references to k
and v
.
I tried:
for(std::tie(k,v) : map)
{
std::cout << "k=" << k << " - " << v << std::endl;
}
and
auto i = std::tie(k,v);
for(i : map)
{
std::cout << "k=" << k << " - " << v << std::endl;
}
But none of the ranged based for loop ideas seemed to work. Presumably the ranged based for loop is required to have a declaration before the :
, since even:
std::vector<int> test;
int i;
for (i : test);
Isn't valid.
The closest equivalent I can find is:
for (auto it = map.begin(); it!=map.end() && (std::tie(k,v)=*it,1); ++it)
{
std::cout << "k=" << k << " - " << v << std::endl;
}
which isn't quite as succinct as the BOOST_FOREACH
version!
Is there a way to express the same thing succinctly without boost in C++11?
回答1:
for (auto & i : map)
{
std::tie(k,v) = i;
// your code here
}
回答2:
This produces the same output as the Boost macro
for( auto const& k : map ) {
std::cout << "k = " << k.first << " - " << k.second << std::endl;
}
回答3:
With C++17 this can now be done using structured bindings, for instance:
#include <map>
#include <string>
#include <iostream>
int main() {
const std::map<std::string, std::string> map = {std::make_pair("hello", "world")};
for (auto& [k,v]: map) {
std::cout << "k=" << k << ", v=" << v << "\n";
}
}
This is certainly what I'd choose to do in newer projects.
来源:https://stackoverflow.com/questions/10523648/replace-boost-foreach-with-pure-c11-alternative