SQL Group By with an Order By

大城市里の小女人 提交于 2019-11-26 21:33:51

In all versions of MySQL, simply alias the aggregate in the SELECT list, and order by the alias:

SELECT COUNT(id) AS theCount, `Tag` from `images-tags`
GROUP BY `Tag`
ORDER BY theCount DESC
LIMIT 20

MySQL prior to version 5 did not allow aggregate functions in ORDER BY clauses.

You can get around this limit with the deprecated syntax:

SELECT COUNT(id), `Tag` from `images-tags`
GROUP BY `Tag`
ORDER BY 1 DESC
LIMIT 20

1, since it's the first column you want to group on.

I don't know about MySQL, but in MS SQL, you can use the column index in the order by clause. I've done this before when doing counts with group bys as it tends to be easier to work with.

So

SELECT COUNT(id), `Tag` from `images-tags`
GROUP BY `Tag`
ORDER BY COUNT(id) DESC
LIMIT 20

Becomes

SELECT COUNT(id), `Tag` from `images-tags`
GROUP BY `Tag`
ORDER 1 DESC
LIMIT 20

In Oracle, something like this works nicely to separate your counting and ordering a little better. I'm not sure if it will work in MySql 4.

select 'Tag', counts.cnt
from
  (
  select count(*) as cnt, 'Tag'
  from 'images-tags'
  group by 'tag'
  ) counts
order by counts.cnt desc

You can get around this limit with the deprecated syntax: ORDER BY 1 DESC

This syntax is not deprecated at all, it's E121-03 from SQL99.

Ashutosh Gupta

Try this query

 SELECT  data_collector_id , count (data_collector_id ) as frequency 
    from rent_flats 
    where is_contact_person_landlord = 'True' 
    GROUP BY data_collector_id 
    ORDER BY count(data_collector_id) DESC
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