Emacs Lisp: getting ascii value of character

谁都会走 提交于 2019-12-05 05:19:31

String is an array.

(aref "foo" 0)

To get the ascii-number which represents the character --as Drew said-- put a question mark before the character and evaluate that expression

?a ==> 97

Number appears in minibuffer, with C-u it's written behind expression.

Also the inverse works

(insert 97) will insert an "a" in the buffer.

BTW In some cases the character should be quoted

?\" will eval to 34

A character is a whole number in Emacs Lisp. There is no separate character data type.

Function string-to-char is built-in, and does what you want. (string-to-char "foo") is equivalent to (aref "foo" 0), which is @abo-abo's answer --- but it is coded in C.

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