How to use youtube-dl from a python program

I would like to access the result of the shell command:

youtube-dl -g "www.youtube.com..."

to print its output direct url to file; from within a python program:

import youtube-dl
fromurl="www.youtube.com ...."
geturl=youtube-dl.magiclyextracturlfromurl(fromurl)

Is that possible ? I tried to understand the mechanism in the source but got lost : youtube_dl/__init__.py, youtube_dl/youtube_DL.py, info_extractors ...

jaimeMF

It's not difficult and actually documented:

import youtube_dl

ydl = youtube_dl.YoutubeDL({'outtmpl': '%(id)s%(ext)s'})

with ydl:
    result = ydl.extract_info(
        'http://www.youtube.com/watch?v=BaW_jenozKc',
        download=False # We just want to extract the info
    )

if 'entries' in result:
    # Can be a playlist or a list of videos
    video = result['entries'][0]
else:
    # Just a video
    video = result

print(video)
video_url = video['url']
print(video_url)

Here is a way.

We set-up options' string, in a list, just as we set-up command line arguments. In this case opts=['-g', 'videoID']. Then, invoke youtube_dl.main(opts). In this way, we write our custom .py module, import youtube_dl and then invoke the main() function.

I would like this

from subprocess import call

command = "youtube-dl https://www.youtube.com/watch?v=NG3WygJmiVs -c"
call(command.split(), shell=False)

If youtube-dl is a terminal program, you can use the subprocess module to access the data you want.

Check out this link for more details: Calling an external command in Python

来源：https://stackoverflow.com/questions/18054500/how-to-use-youtube-dl-from-a-python-program

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python

youtube-dl