How does Zend Framework 2 render partials inside a module?

丶灬走出姿态 提交于 2019-12-03 06:03:21

this can be achieved by

 echo $this->partial('layout/header', array('vr' => 'zf2'));

you can access the variable in view using

echo $this->vr;

don't forget to add following line in your view_manager of module.config.php file.

'layout/header'           => __DIR__ . '/../view/layout/header.phtml',  

after adding it looks like this

return array(  

'view_manager' => array(
        'template_path_stack' => array(
            'user' => __DIR__ . '/../view' ,
        ),
        'display_not_found_reason' => true,
        'display_exceptions'       => true,
        'doctype'                  => 'HTML5',
        'not_found_template'       => 'error/404',
        'exception_template'       => 'error/index',
        'template_map' => array(
            'layout/layout'           => __DIR__ . '/../view/layout/layout.phtml',

            'layout/header'           => __DIR__ . '/../view/layout/header.phtml',            

            'error/404'               => __DIR__ . '/../view/error/404.phtml',
            'error/index'             => __DIR__ . '/../view/error/index.phtml',
        ),


    ),    

);

Have you tried to include the name of your module in the called to the View Helper partial()?

http://packages.zendframework.com/docs/latest/manual/en/zend.view.helpers.html#zend.view.helpers.initial.partial.modules

<?php echo $this->partial('pager.phtml', 'list', $pagerData) ?>
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