Drop marker slowly from top of screen to location on android map V2

拜拜、爱过 提交于 2019-12-02 21:30:34

You can achieve this with a code similar to this (untested):

final LatLng target = ...;

final long duration = 400;
final Handler handler = new Handler();
final long start = SystemClock.uptimeMillis();
Projection proj = map.getProjection();

Point startPoint = proj.toScreenLocation(target);
startPoint.y = 0;
final LatLng startLatLng = proj.fromScreenLocation(startPoint);

final Interpolator interpolator = new LinearInterpolator();
handler.post(new Runnable() {
    @Override
    public void run() {
        long elapsed = SystemClock.uptimeMillis() - start;
        float t = interpolator.getInterpolation((float) elapsed / duration);
        double lng = t * target.longitude + (1 - t) * startLatLng.longitude;
        double lat = t * target.latitude + (1 - t) * startLatLng.latitude;
        marker.setPosition(new LatLng(lat, lng));
        if (t < 1.0) {
            // Post again 10ms later.
            handler.postDelayed(this, 10);
        } else {
            // animation ended
        }
    }
});

I have combined the MaciejGórski's approach with the code from this gist. In addition, added a bounce effect.

public class MyBounceInterpolator implements android.view.animation.Interpolator {
    double mAmplitude = 1;
    double mFrequency = 10;

    public MyBounceInterpolator(double amplitude, double frequency) {
        mAmplitude = amplitude;
        mFrequency = frequency;
    }

    public float getInterpolation(float time) {
        double amplitude = mAmplitude;
        if (amplitude == 0) { amplitude = 0.05; }

        // The interpolation curve equation:
        //    -e^(-time / amplitude) * cos(frequency * time) + 1
        //
        // View the graph live: https://www.desmos.com/calculator/6gbvrm5i0s
        return (float) (-1 * Math.pow(Math.E, -time/ mAmplitude) * Math.cos(mFrequency * time) + 1);
    }
}

void dropMarker(final Marker marker, GoogleMap map) {
    final LatLng finalPosition = new LatLng(marker.getPosition().latitude, marker.getPosition().longitude);

    Projection projection = map.getProjection();
    Point startPoint = projection.toScreenLocation(finalPosition);
    startPoint.y = 0;
    final LatLng startLatLng = projection.fromScreenLocation(startPoint);
    final Interpolator interpolator = new MyBounceInterpolator(0.11, 4.6);

    TypeEvaluator<LatLng> typeEvaluator = new TypeEvaluator<LatLng>() {
        @Override
        public LatLng evaluate(float fraction, LatLng startValue, LatLng endValue) {
            float t = interpolator.getInterpolation(fraction);
            double lng = t * finalPosition.longitude + (1 - t) * startLatLng.longitude;
            double lat = t * finalPosition.latitude + (1 - t) * startLatLng.latitude;
            return new LatLng(lat, lng);
        }
    };

    Property<Marker, LatLng> property = Property.of(Marker.class, LatLng.class, "position");
    ObjectAnimator animator = ObjectAnimator.ofObject(marker, property, typeEvaluator, finalPosition);
    animator.setDuration(400);
    animator.start();
}

It works great, but it seemed to me that sometimes the marker remained one step far from the target, so I added just one more line:

if (t < 1.0) {
    // Post again 10ms later.
    handler.postDelayed(this, 50);
} else {
    // animation ended
    marker.setPosition(target);
}

Hope it helps.

I've applied your way but have an issue that is the markers position on map is not correct. I think command below calculate is not correct. So after animation finished then final result is not same as original Lat,Lng.

double lng = t * target.longitude + (1 - t) * startLatLng.longitude; double lat = t * target.latitude + (1 - t) * startLatLng.latitude;

易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!