问题
I have 5 attachments whose paths are stored in database (5) columns. I am retrieving the paths as follows for the first file.
$path1=$rowArray['file1'];
$path2=$rowArray['file2'];
<?php printf('<a href="%s" >View all Files</a>',$path1); ?>
where $path1 is the path of the first file, and by clicking on View all Files, the image is shown on the next page.
I want to show all the 5 images on the same page under View all Files links.
How can i do it. Hope u all understand. I have applied a loop to show, them all, but it doesnot help. Please provide me a valid solution for this.
回答1:
No doubt you cannot do it the way you want, with one link, show all your images. I guess the best way to do it is to send the file names or ids on your URL and check for it on your target PHP, this way you can show them.
回答2:
you need javascript for that, an hover on the links would create a div with the image/s which src attribute would be the link's path..
来源：https://stackoverflow.com/questions/10196929/retrieving-images-from-database-and-displaying-all-on-a-page